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Chapter 11: Problem 51

Which solvent, water or carbon tetrachloride, would you choose to dissolve each of the following? a. \(\mathrm{KrF}_{2}\) b. \(\mathrm{SF}_{2}\) c. \(\mathrm{SO}_{2}\) d. \(\mathrm{CO}_{2}\) e. \(M g F_{2}\) f. \(C H_{2} O\) g. \(C H_{2}=C H_{2}\)

Short Answer

Expert verified
a. Carbon tetrachloride for KrF₂ (nonpolar) b. Water for SF₂ (polar) c. Water for SO₂ (polar) d. Carbon tetrachloride for CO₂ (nonpolar) e. Water for MgF₂ (ionic) f. Water for CH₂O (polar) g. Carbon tetrachloride for CH₂=CH₂ (nonpolar)

Step by step solution

01

a. KrF₂

KrF₂ is a nonpolar substance. Nonpolar substances dissolve better in nonpolar solvents. Therefore, it is better to use carbon tetrachloride to dissolve KrF₂.
02

b. SF₂

SF₂ is a polar substance. Polar substances dissolve better in polar solvents. Therefore, it is better to use water to dissolve SF₂.
03

c. SO₂

SO₂ is a polar substance. Polar substances dissolve better in polar solvents. Therefore, it is better to use water to dissolve SO₂.
04

d. CO₂

CO₂ is a nonpolar substance. Nonpolar substances dissolve better in nonpolar solvents. Therefore, it is better to use carbon tetrachloride to dissolve CO₂.
05

e. MgF₂

MgF₂ is an ionic compound, which means it contains positively and negatively charged ions. Ionic compounds dissolve better in polar solvents. Therefore, it is better to use water to dissolve MgF₂.
06

f. CH₂O

CH₂O has a bent molecular geometry, which makes it polar. Polar substances dissolve better in polar solvents. Therefore, it is better to use water to dissolve CH₂O.
07

g. CH₂=CH₂

CH₂=CH₂ is a nonpolar substance due to its linear molecular geometry and equal sharing of electrons between carbon atoms. Nonpolar substances dissolve better in nonpolar solvents. Therefore, it is better to use carbon tetrachloride to dissolve CH₂=CH₂.

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Most popular questions from this chapter

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