Which ion in each of the following pairs would you expect to be more strongly hydrated? Why? a. \(\mathrm{Na}^{+}\) or \(\mathrm{Mg}^{2+}\) b. \(\mathrm{Mg}^{2+}\) or \(\mathrm{Be}^{2+}\) c. \(\mathrm{Fe}^{2+}\) or \(\mathrm{Fe}^{3+}\) d. \(\mathrm{F}^{-}\) or \(\mathrm{Br}^{-}\) e. \(\mathrm{Cl}^{-}\) or \(\mathrm{ClO}_{4}^{-}\) f. \(\mathrm{ClO}_{4}^{-}\) or \(\mathrm{SO}_{4}^{2-}\)

Short Answer

Expert verified
a. \(\mathrm{Mg}^{2+}\) is more strongly hydrated because it has a higher charge than \(\mathrm{Na}^{+}\). b. \(\mathrm{Be}^{2+}\) is more strongly hydrated because it has a smaller atomic radius than \(\mathrm{Mg}^{2+}\). c. \(\mathrm{Fe}^{3+}\) is more strongly hydrated because it has a higher charge than \(\mathrm{Fe}^{2+}\). d. \(\mathrm{F}^{-}\) is more strongly hydrated because it has a smaller atomic radius than \(\mathrm{Br}^{-}\). e. \(\mathrm{Cl}^{-}\) is more strongly hydrated because it has a higher effective charge density than \(\mathrm{ClO}_{4}^{-}\). f. \(\mathrm{SO}_{4}^{2-}\) is more strongly hydrated because it has a higher negative charge than \(\mathrm{ClO}_{4}^{-}\).

Step by step solution

01

Compare the charges of each ion.

Since \(\mathrm{Mg}^{2+}\) has a higher charge than \(\mathrm{Na}^{+}\), it is more strongly hydrated. b. \(\mathrm{Mg}^{2+}\) or \(\mathrm{Be}^{2+}\)
02

Compare the sizes of each ion.

Since both ions, \(\mathrm{Mg}^{2+}\) and \(\mathrm{Be}^{2+}\), have the same charges, we need to compare their sizes. Be has a smaller atomic radius than Mg so, \(\mathrm{Be}^{2+}\) will be more strongly hydrated. c. \(\mathrm{Fe}^{2+}\) or \(\mathrm{Fe}^{3+}\)
03

Compare the charges of each ion.

Since \(\mathrm{Fe}^{3+}\) has a higher charge than \(\mathrm{Fe}^{2+}\), it is more strongly hydrated. d. \(\mathrm{F}^{-}\) or \(\mathrm{Br}^{-}\)
04

Compare the sizes of each ion.

Since both ions, \(\mathrm{F}^{-}\) and \(\mathrm{Br}^{-}\) have equal charges, we need to compare their sizes. F has a smaller atomic radius than Br, so \(\mathrm{F}^{-}\) will be more strongly hydrated. e. \(\mathrm{Cl}^{-}\) or \(\mathrm{ClO}_{4}^{-}\)
05

Compare the effective charge densities of each ion.

Though both ions have equal charges, the \(\mathrm{ClO}_{4}^{-}\) ion is much larger compared to the \(\mathrm{Cl}^{-}\) ion due to the presence of the oxygen atoms. Therefore, \(\mathrm{Cl}^{-}\) has a higher effective charge density than \(\mathrm{ClO}_{4}^{-}\) and will be more strongly hydrated. f. \(\mathrm{ClO}_{4}^{-}\) or \(\mathrm{SO}_{4}^{2-}\)
06

Compare the charges of each ion.

Since \(\mathrm{SO}_{4}^{2-}\) has a higher negative charge than \(\mathrm{ClO}_{4}^{-}\), it is more strongly hydrated.

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