Table 12.2 illustrates how the average rate of a reaction decreases with time. Why does the average rate of a reaction generally decrease with time? How does the instantaneous rate of a reaction depend on time? Why are initial rates of a reaction primarily used by convention?

Short Answer

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The average rate of a reaction generally decreases with time because, as the reaction progresses, the concentrations of reactants decrease, leading to fewer reactant particles available to collide and react. The instantaneous rate of a reaction is the rate at which reactants are consumed or products are generated at an exact moment in time (\(\frac{d[R]}{dt}\) or \(\frac{d[P]}{dt}\) respectively), and may decrease, increase, or remain constant with time, depending on the reaction and the orders of reactants. Initial rates of a reaction are primarily used by convention because they offer a consistent starting point for comparing reactions, are easier to determine experimentally, and help researchers to understand the reaction mechanisms by determining the rate law (order and rate constant).

Step by step solution

01

Understanding Average Reaction Rates

The average rate of a chemical reaction refers to the speed at which reactants are transformed into products over a certain time interval. As the reaction progresses, the concentrations of the reactants decrease, which generally leads to a slower reaction rate. Since there are fewer reactant particles available to collide and react, the overall average rate of the reaction decreases with time.
02

Instantaneous Reaction Rates and Time

The instantaneous rate of a reaction is the rate at which reactants are consumed or products are generated at an exact moment in time. Mathematically, it is the derivative of the concentration of reactants or products with respect to time (\(\frac{d[R]}{dt}\) or \(\frac{d[P]}{dt}\) respectively). Depending on the reaction and the orders of the reactants, the instantaneous rate may either decrease, increase, or remain constant with time. However, oftentimes, it will follow a similar trend to the average rate, decreasing as the reaction progresses and reactant concentrations drop.
03

Use of Initial Rates in Reactions

Initial rates are reaction rates measured at the beginning of a reaction when the concentration of reactants is at its highest. There are a few reasons why initial rates are primarily used by convention: 1. The initial rate offers a consistent starting point for comparing reactions, as it eliminates the impact of changing concentrations as the reaction progresses. 2. Initial rates are easier to determine experimentally and can provide a clear indication of how changing reactants' concentrations affect the overall rate of a chemical reaction. 3. The initial rates are useful to determine the rate law (order and rate constant) in kinetics studies, helping researchers to understand the reaction mechanisms. In summary, understanding the behavior of reaction rates, such as average and instantaneous rates, is crucial in the study of chemical kinetics. Initial rates are primarily used to simplify and standardize the study of reactions and better understand their mechanisms.

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Most popular questions from this chapter

The reaction $$ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g) $$ exhibits the rate law $$ \text {Rate} =k[\mathrm{NO}]^{2}\left[\mathrm{O}_{2}\right] $$ Which of the following mechanisms is consistent with this rate law? $$ \begin{array}{l}{\text { a. } \mathrm{NO}+\mathrm{O}_{2} \longrightarrow \mathrm{NO}_{2}+\mathrm{O}} \\ {\mathrm{O}+\mathrm{NO} \longrightarrow \mathrm{NO}_{2}} \\ {\text { b. } \mathrm{NO}+\mathrm{O}_{2} \rightleftharpoons \mathrm{NO}_{3}} \\ {\mathrm{NO}_{3}+\mathrm{NO} \longrightarrow 2 \mathrm{NO}_{2}}\end{array} $$ $$ \begin{array}{l}{\text { c. } 2 \mathrm{NO} \longrightarrow \mathrm{N}_{2} \mathrm{O}_{2}} \\ {\mathrm{N}_{2} \mathrm{O}_{2}+\mathrm{O}_{2} \longrightarrow \mathrm{N}_{2} \mathrm{O}_{4}} \\ {\mathrm{N}_{2} \mathrm{O}_{4} \longrightarrow 2 \mathrm{NO}_{2}} \\ {\text { d. } 2 \mathrm{NO} \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{2}} \\\ {\mathrm{N}_{2} \mathrm{O}_{2} \longrightarrow \mathrm{NO}_{2}+\mathrm{O}} \\\ {\mathrm{O}+\mathrm{NO} \longrightarrow \mathrm{NO}_{2}}\end{array} $$

Assuming that the mechanism for the hydrogenation of $\mathrm{C}_{2} \mathrm{H}_{4}$ given in Section 12.7 is correct, would you predict that the product of the reaction of \(\mathrm{C}_{2} \mathrm{H}_{4}\) with \(\mathrm{D}_{2}\) would be $\mathrm{CH}_{2} \mathrm{D}-\mathrm{CH}_{2} \mathrm{D}\( or \)\mathrm{CHD}_{2}-\mathrm{CH}_{3} ?$ How could the reaction of \(\mathrm{C}_{2} \mathrm{H}_{4}\) with \(\mathrm{D}_{2}\) be used to confirm the mechanism for the hydrogenation of \(\mathrm{C}_{2} \mathrm{H}_{4}\) given in Section 12.7\(?\)

Define stability from both a kinetic and thermodynamic perspective. Give examples to show the differences in these concepts.

The rate law for the reaction $$ \begin{array}{c}{\mathrm{Cl}_{2}(g)+\mathrm{CHCl}_{3}(g) \longrightarrow \mathrm{HCl}(g)+\mathrm{CCl}_{4}(g)} \\ {\text { Rate }=k\left[\mathrm{Cl}_{2}\right]^{1 / 2}\left[\mathrm{CHCl}_{3}\right]}\end{array} $$ What are the units for \(k,\) assuming time in seconds and concentration in mol/L?

Chemists commonly use a rule of thumb that an increase of 10 \(\mathrm{K}\) in temperature doubles the rate of a reaction. What must the activation energy be for this statement to be true for a temperature increase from 25 to \(35^{\circ} \mathrm{C} ?\)

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