For a typical equilibrium problem, the value of \(K\) and the initial reaction conditions are given for a specific reaction, and you are asked to calculate the equilibrium concentrations. Many of these calculations involve solving a quadratic or cubic equation. What can you do to avoid solving a quadratic or cubic equation and still come up with reasonable equilibrium concentrations?

Short Answer

Expert verified
To find reasonable equilibrium concentrations without solving quadratic or cubic equations, follow these steps: 1. Identify the reaction and equilibrium expression by writing down the given chemical reaction and corresponding equilibrium expression. 2. Determine the initial concentrations of the reacting species given in the problem. 3. Write the changes in concentrations at equilibrium using an ICE (Initial, Change, Equilibrium) table and consider a change of x in the concentration of products and -x for reactants. 4. Approximate the value of x by comparing the value of the equilibrium constant K with the initial concentrations. If K is much smaller (about three orders of magnitude smaller) than the initial concentrations, approximate x with zero in the denominator of the equilibrium constant expression. 5. Calculate the equilibrium concentrations using the approximation for x and check if the result matches the given equilibrium constant (K) closely. If the results are acceptable, these calculated equilibrium concentrations can be used without solving quadratic or cubic equations. This method works well for most weak acids, bases, and weakly interacting systems but requires verification of the approximation's accuracy.

Step by step solution

01

Identify the reaction and equilibrium expression

Write down the given chemical reaction, and then write down the equilibrium expression based on the chemical species involved.
02

Determine the initial concentrations

Determine and list all the initial concentrations of the reacting species given in the problem.
03

Write the changes in concentrations at equilibrium

Assuming that the reaction has reached equilibrium, create an ICE (Initial, Change, Equilibrium) table to represent the changes in the reacting species' concentrations during the reaction. Consider a change of x in the concentration of products and -x for reactants. For example, for a reaction aA + bB <=> cC + dD, ICE table columns: Initial, Change, and Equilibrium concentrations ICE table rows: concentration of A, concentration of B, concentration of C, and concentration of D
04

Approximate the value of x

Compare the value of the equilibrium constant K with the initial concentrations of the reacting species. If K is much smaller (about three orders of magnitude smaller) than the initial concentrations, we can make a reasonable assumption that the change in concentration, x, is very small compared to the initial concentrations. Therefore, we can approximate the value of x with zero in the denominator of the equilibrium constant expression. For example, in a 1:1 reaction A <=> B with an initial concentration of A as 1.0 M and K as 1.0 x 10^(-6), we can assume that the change x is very small since K is much smaller than the initial concentration.
05

Calculate the equilibrium concentrations

Using the approximation for x, calculate the equilibrium concentrations for the reactants and products with the new, simpler expression for the equilibrium constant. Plug these values into the original equilibrium expression, and check if the result matches the given equilibrium constant (K) closely. If the results are acceptable, you can use these calculated equilibrium concentrations without solving quadratic or cubic equations. In conclusion, when the equilibrium constant K is much smaller than the initial concentrations, we can avoid solving quadratic or cubic equations using this approximation method. This method works well for most weak acids, bases, and other weakly interacting systems. However, it is essential to verify the accuracy of the approximation by checking the final calculated equilibrium constant against the given value of K.

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Most popular questions from this chapter

For the reaction $\mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \rightleftharpoons 2 \mathrm{HI}(g),$ consider two possibilities: (a) you mix 0.5 mole of each reactant, allow the system to come to equilibrium, and then add another mole of \(\mathrm{H}_{2}\) and allow the system to reach equilibrium again, or \((b)\) you \(\operatorname{mix} 1.5\) moles of \(\mathrm{H}_{2}\) and 0.5 mole of \(\mathrm{I}_{2}\) and allow the system to reach equilibrium. Will the final equilibrium mixture be different for the two procedures? Explain.

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Consider the reaction $\mathrm{A}(g)+\mathrm{B}(g) \rightleftharpoons \mathrm{C}(g)+\mathrm{D}(g) . \mathrm{A}$ friend asks the following: “I know we have been told that if a mixture of A, B, C, and D is at equilibrium and more of A is added, more C and D will form. But how can more C and D form if we do not add more B?” What do you tell your friend?

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A sample of \(\mathrm{N}_{2} \mathrm{O}_{4}(g)\) is placed in an empty cylinder at \(25^{\circ} \mathrm{C}\) . After equilibrium is reached the total pressure is 1.5 atm and 16\(\%\) (by moles) of the original $\mathrm{N}_{2} \mathrm{O}_{4}(g)\( has dissociated to \)\mathrm{NO}_{2}(g) .$ a. Calculate the value of \(K_{\mathrm{p}}\) for this dissociation reaction at \(25^{\circ} \mathrm{C} .\) b. If the volume of the cylinder is increased until the total pressure is 1.0 atm (the temperature of the system remains constant), calculate the equilibrium pressure of \(\mathrm{N}_{2} \mathrm{O}_{4}(g)\) and \(\mathrm{NO}_{2}(g) .\) c. What percentage (by moles) of the original $\mathrm{N}_{2} \mathrm{O}_{4}(g)$ is dissociated at the new equilibrium position (total pressure \(=1.00 \mathrm{atm} ) ?\)

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