Place the species in each of the following groups in order of increasing acid strength. Explain the order you chose for each group. a. \(\mathrm{HIO}_{3}, \mathrm{HBrO}_{3}\) b. \(\mathrm{HNO}_{2}, \mathrm{HNO}_{3}\) c. HOCl, HOI d. \(\mathrm{H}_{3} \mathrm{PO}_{4}, \mathrm{H}_{3} \mathrm{PO}_{3}\)

Short Answer

Expert verified
The order of increasing acid strength for each group is: a. \(\mathrm{HBrO}_{3} < \mathrm{HIO}_{3}\) - due to lower electronegativity and larger atomic size of Iodine. b. \(\mathrm{HNO}_{2} < \mathrm{HNO}_{3}\) - due to higher oxidation state of Nitrogen in \(\mathrm{HNO}_{3}\). c. HOI < HOCl - due to higher electronegativity of Chlorine. d. \(\mathrm{H}_{3} \mathrm{PO}_{3} < \mathrm{H}_{3} \mathrm{PO}_{4}\) - due to the additional oxygen atom in \(\mathrm{H}_{3} \mathrm{PO}_{4}\).

Step by step solution

01

Group A: \(\mathrm{HIO}_{3}, \mathrm{HBrO}_{3}\)

To compare the acid strength of \(\mathrm{HIO}_{3}\) and \(\mathrm{HBrO}_{3}\), we need to compare the electronegativity and atomic size of central atoms Iodine (I) and Bromine (Br). 1. Electronegativity: Iodine has a lower electronegativity (2.66) compared to Bromine (2.96). Lower electronegativity means the central atom can hold the bonding electrons less strongly, making it easier for the hydrogen to be lost as a proton. 2. Atomic size: Iodine has a larger atomic size than Bromine. A larger atomic size means the bonding electrons are further from the nucleus, which also makes it easier for the hydrogen to be lost as a proton. Based on these factors, we can conclude that \(\mathrm{HIO}_{3}\) has higher acid strength than \(\mathrm{HBrO}_{3}\). The order of increasing acid strength is \(\mathrm{HBrO}_{3} < \mathrm{HIO}_{3}\).
02

Group B: \(\mathrm{HNO}_{2}, \mathrm{HNO}_{3}\)

In this case, we are comparing the acid strength of two species with the same central atom: Nitrogen. However, they differ in the oxidation state of the nitrogen atom. For \(\mathrm{HNO}_{2}\) (nitrous acid), nitrogen has an oxidation state of +3, while for \(\mathrm{HNO}_{3}\) (nitric acid), nitrogen has an oxidation state of +5. A higher oxidation state means the central atom is more electron-deficient, making the O-H bond more polar and easier to break, thereby increasing the acid strength. Hence, \(\mathrm{HNO}_{3}\) is a stronger acid compared to \(\mathrm{HNO}_{2}\). The order of increasing acid strength is \(\mathrm{HNO}_{2} < \mathrm{HNO}_{3}\).
03

Group C: HOCl, HOI

Here, we need to compare the acid strength of hypochlorous acid (HOCl) and hypoiodous acid (HOI), so we analyze factors concerning the central atoms Chlorine (Cl) and Iodine (I). 1. Electronegativity: Chlorine has a higher electronegativity (3.16) compared to Iodine (2.66). Higher electronegativity means that the O-H bond in HOCl will be more polar compared to HOI, making it easier for the hydrogen to be lost as a proton. 2. Atomic size: Chlorine has a smaller atomic size than Iodine. However, in this case, the higher electronegativity plays a more significant role in determining the acid strength. Based on these factors, we can conclude that HOCl has higher acid strength than HOI. The order of increasing acid strength is HOI < HOCl.
04

Group D: \(\mathrm{H}_{3} \mathrm{PO}_{4}, \mathrm{H}_{3} \mathrm{PO}_{3}\)

In this group, we need to compare the acid strength of two species with the same central atom: Phosphorus. However, they differ in the number of oxygen atoms bonded to the central atom. \(\mathrm{H}_{3} \mathrm{PO}_{4}\) (phosphoric acid) has one more oxygen atom bonded to phosphorus than \(\mathrm{H}_{3} \mathrm{PO}_{3}\) (phosphorous acid). This additional oxygen atom increases the electron deficiency of the phosphorus atom, increasing the polarity of the O-H bonds and making it easier for the hydrogen atoms to be lost as protons. Hence, \(\mathrm{H}_{3} \mathrm{PO}_{4}\) is a stronger acid compared to \(\mathrm{H}_{3} \mathrm{PO}_{3}\). The order of increasing acid strength is \(\mathrm{H}_{3} \mathrm{PO}_{3} < \mathrm{H}_{3} \mathrm{PO}_{4}\).

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Most popular questions from this chapter

A typical vitamin \(\mathrm{C}\) tablet (containing pure ascorbic acid, \(\mathrm{H}_{2} \mathrm{C}_{6} \mathrm{H}_{6} \mathrm{O}_{6}\) ) weighs $500 . \mathrm{mg}\( . One vitamin \)\mathrm{C}$ tablet is dissolved in enough water to make 200.0 \(\mathrm{mL}\) of solution. Calculate the \(\mathrm{pH}\) of this solution. Ascorbic acid is a diprotic acid.

An aqueous solution contains a mixture of 0.0500\(M \mathrm{HCOOH}\) \(\left(K_{\mathrm{a}}=1.77 \times 10^{-4}\right)\) and 0.150$M \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\left(K_{\mathrm{a}}=\right.\( \)1.34 \times 10^{-5} ) .\( Calculate the \)\mathrm{pH}$ of this solution. Because both acids are of comparable strength, the \(\mathrm{H}^{+}\) contribution from both acids must be considered.

A solution is made by adding 50.0 \(\mathrm{mL}\) of 0.200\(M\) acetic acid \(\left(K_{\mathrm{a}}=1.8 \times 10^{-5}\right)\) to 50.0 \(\mathrm{mL}\) of \(1.00 \times 10^{-3} \mathrm{M} \mathrm{HCl}\) a. Calculate the pH of the solution. b. Calculate the acetate ion concentration.

Hemoglobin (abbreviated Hb) is a protein that is responsible for the transport of oxygen in the blood of mammals. Each hemoglobin molecule contains four iron atoms that are the binding sites for \(\mathrm{O}_{2}\) molecules. The oxygen binding is pH- dependent. The relevant equilibrium reaction is $$ \mathrm{HbH}_{4}^{4+}(a q)+4 O_{2}(g) \rightleftharpoons \mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4}(a q)+4 \mathrm{H}^{+}(a q) $$ Use Le Châtelier's principle to answer the following. a. What form of hemoglobin, HbH \(_{4}^{4+}\) or \(\mathrm{Hb}\left(\mathrm{O}_{2}\right)_{4},\) is favored in the lungs? What form is favored in the cells? b. When a person hyperventilates, the concentration of \(\mathrm{CO}_{2}\) in the blood is decreased. How does this affect the oxygen-binding equilibrium? How does breathing into a paper bag help to counteract this effect? (See Exercise \(146 .\) ) c. When a person has suffered a cardiac arrest, injection of a sodium bicarbonate solution is given. Why is this necessary? (Hint: CO, blood levels increase during cardiac arrest.)

Which of the following represent conjugate acid-base pairs? For those pairs that are not conjugates, write the correct conjugate acid or base for each species in the pair. a. \(\mathrm{H}_{2} \mathrm{O}, \mathrm{OH}^{-}\) b. \(\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{SO}_{4}^{2-}\) c. \(\mathrm{H}_{3} \mathrm{PO}_{4}, \mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) d. $\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}, \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}^{-}$

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