Sketch the titration curves for a diprotic acid titrated by a strong base and a triprotic acid titrated by a strong base. List the major species present at various points in each curve. In each curve, label the halfway points to equivalence. How do you calculate the pH at these halfway points?

Short Answer

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The titration curve for a diprotic acid titrated with a strong base has two equivalence points and two buffer regions, and for a triprotic acid, it has three equivalence points and three buffer regions. Major species present at various points include the unreacted acid, deprotonated species, and the completely deprotonated species. Halfway points to equivalence can be calculated with the ratio of moles of base to moles of acid. To find the pH at these halfway points, the pH is equal to the pKa value of the corresponding acidic group: \( pH = pKa = -\log_{10}(Ka) \).

Step by step solution

01

Describe the general shape of the titration curve for diprotic and triprotic acids

For a diprotic acid, the titration curve will have two equivalence points and two buffer regions, while for a triprotic acid, the titration curve will have three equivalence points and three buffer regions. In both cases, the curve will start from a relatively low pH and end at a higher pH, as the strong base reacts with each acidic group one at a time.
02

Identify major species at various points on the curve.

Throughout the titration, several species will be present depending on the degree of reaction with the base: - At the beginning of the titration, the major species will be the unreacted diprotic/triprotic acid (H2A or H3A). - At the first buffer region, the major species will be a mixture of the first deprotonated species (HA- or H2A-) and the corresponding acid. - At the second buffer region for diprotic and first buffer region for triprotic acids, the major species will be a mixture of the second deprotonated species (A2- or HA2-) and the corresponding acid. - For triprotic acids, at the third buffer region, the major species will be a mixture of the third deprotonated species (A3-) and the corresponding acid. - At the final point of the titration, the major species will be the completely deprotonated species (A2- or A3-).
03

Identify and label the halfway points to equivalence.

The halfway points are where half of the acidic groups have reacted with the strong base. We can calculate these points by finding the ratio of moles of base to moles of acid: - For diprotic acids: - Halfway to the first equivalence point: moles of base = 0.5 * moles of acid - Halfway to the second equivalence point: moles of base = 1.5 * moles of acid - For triprotic acids: - Halfway to the first equivalence point: moles of base = 0.5 * moles of acid - Halfway to the second equivalence point: moles of base = 1.5 * moles of acid - Halfway to the third equivalence point: moles of base = 2.5 * moles of acid
04

Calculate the pH at the halfway points.

At the halfway points, the pH is equal to the pKa value of the corresponding acidic group. To calculate the pH at these points, use the formula: \( pH = pKa = -\log_{10}(Ka) \) where Ka is the acid dissociation constant for the particular acidic group.

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Most popular questions from this chapter

Consider the titration of 50.0 \(\mathrm{mL}\) of 0.10$M \mathrm{H}_{3} \mathrm{A}\left(K_{\mathrm{a}},=\right.\( \)5.0 \times 10^{-4}, K_{\mathrm{a}_{2}}=1.0 \times 10^{-8}, K_{\mathrm{a}_{2}}=1.0 \times 10^{-11}$ ) titrated by 0.10\(M \mathrm{KOH}\) a. Calculate the pH of the resulting solution at 125 \(\mathrm{mL}\) of KOH added. b. At what volume of KOH added does pH \(=3.30 ?\) c. At 75.0 \(\mathrm{mL}\) of KOH added, is the solution acidic or basic?

Consider the titration of 150.0 \(\mathrm{mL}\) of 0.100 $\mathrm{M} \mathrm{HI}\( by 0.250 \)\mathrm{M}\( \)\mathrm{NaOH}$ . a. Calculate the pH after 20.0 \(\mathrm{mL}\) of NaOH has been added. b. What volume of NaOH must be added so that the \(\mathrm{pH}=7.00 ?\)

a. Calculate the \(\mathrm{pH}\) of a buffered solution that is 0.100 \(\mathrm{M}\) in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H}\) (benzoic acid, \(K_{\mathrm{a}}=6.4 \times 10^{-5} )\) and 0.100 \(\mathrm{M}\) in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{Na}\) b. Calculate the pH after 20.0\(\%\) (by moles) of the benzoic acid is converted to benzoate anion by addition of a strong base. Use the dissociation equilibrium $$ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H}(a q) \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2}^{-}(a q)+\mathrm{H}^{+}(a q) $$ to calculate the pH. c. Do the same as in part b, but use the following equilibrium to calculate the \(\mathrm{pH} :\) $$ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H}(a q)+\mathrm{OH}^{-}(a q) $$ d. Do your answers in parts \(b\) and \(c\) agree? Explain.

Sketch the titration curve for the titration of a generic weak base \(\mathrm{B}\) with a strong acid. The titration reaction is $$ \mathrm{B}+\mathrm{H}^{+} \rightleftharpoons \mathrm{BH}^{+} $$ On this curve, indicate the points that correspond to the following: a. the stoichiometric (equivalence) point b. the region with maximum buffering c. \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\) d. \(\mathrm{pH}\) depends only on \([\mathrm{B}]\) e. \(\mathrm{pH}\) depends only on \(\left[\mathrm{BH}^{+}\right]\) f. \(\mathrm{pH}\) depends only on the amount of excess strong acid added

Mixing together solutions of acetic acid and sodium hydroxide can make a buffered solution. Explain. How does the amount of each solution added change the effectiveness of the buffer?

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