Sketch the titration curve for the titration of a generic weak base \(\mathrm{B}\) with a strong acid. The titration reaction is $$ \mathrm{B}+\mathrm{H}^{+} \rightleftharpoons \mathrm{BH}^{+} $$ On this curve, indicate the points that correspond to the following: a. the stoichiometric (equivalence) point b. the region with maximum buffering c. \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\) d. \(\mathrm{pH}\) depends only on \([\mathrm{B}]\) e. \(\mathrm{pH}\) depends only on \(\left[\mathrm{BH}^{+}\right]\) f. \(\mathrm{pH}\) depends only on the amount of excess strong acid added

Short Answer

Expert verified
The titration curve starts with a pH dependent on the weak base concentration \([\mathrm{B}]\) (point d). It reaches maximum buffering around the \(pK_{\mathrm{a}}\) value, where equal concentrations of \(\mathrm{B}\) and \(\mathrm{BH}^{+}\) occur (points a, b, and c). At the stoichiometric point, all \(\mathrm{B}\) has been converted to \(\mathrm{BH}^{+}\), and the pH depends on \(\left[\mathrm{BH}^{+}\right]\) (point e). Beyond the stoichiometric point, the pH depends on the excess strong acid added (point f).

Step by step solution

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1. Overview of titration of a weak base with a strong acid

In this titration, a weak base \(\mathrm{B}\) is titrated with a strong acid. The titration reaction is: \[ \mathrm{B}+\mathrm{H}^{+} \rightleftharpoons \mathrm{BH}^{+} \] Initially, only the weak base is present in the solution. As we add the strong acid, the weak base is converted into its conjugate acid, \(\mathrm{BH}^{+}\). This causes a change in pH throughout the titration process.
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2. Stoichiometric (equivalence) point

The stoichiometric (equivalence) point is reached when the moles of \(\mathrm{H}^+\) added equals the initial moles of \(\mathrm{B}\). At this point, all the weak base has been converted into its conjugate acid, and the pH can be calculated using the weak acid's \(K_{\mathrm{a}}\).
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3. Region with maximum buffering

The region with maximum buffering occurs when the solution can resist changes in pH to the greatest extent. This occurs when a solution contains equal concentrations of \(\mathrm{B}\) and \(\mathrm{BH}^{+}\), resulting in a pH close to the \(pK_{\mathrm{a}}\) value of the conjugate acid.
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4. \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\)

At the point where \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\), there are equal concentrations of the weak base, \(\mathrm{B}\), and its conjugate acid, \(\mathrm{BH}^{+}\).
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5. \(\mathrm{pH}\) depends only on \([\mathrm{B}]\)

Initially, when only the weak base is present in the solution, the pH depends only on the concentration of the weak base, \([\mathrm{B}]\). This is before any strong acid has been added.
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6. \(\mathrm{pH}\) depends only on \(\left[\mathrm{BH}^{+}\right]\)

At the stoichiometric point, all of the weak base has been converted into its conjugate acid, \(\mathrm{BH}^{+}\). So, at this point, the pH depends only on the concentration of the conjugate acid, \(\left[\mathrm{BH}^{+}\right]\).
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7. \(\mathrm{pH}\) depends only on the amount of excess strong acid added

Beyond the stoichiometric point, the pH depends only on the excess strong acid that has been added, as all the weak base has been converted to its conjugate acid and does not affect the pH any further.
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8. Sketching the titration curve

Now, we'll sketch the titration curve and indicate the points described above: - The initial pH (before adding any strong acid) depends only on \([\mathrm{B}]\) (point d). - The region with maximum buffering occurs at \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\), where there are equal concentrations of \(\mathrm{B}\) and \(\mathrm{BH}^{+}\) (point a, b, and c). - At the stoichiometric point, the pH depends only on \(\left[\mathrm{BH}^{+}\right]\) (point e). - Beyond the stoichiometric point, the pH depends only on the amount of excess strong acid added (point f). In summary, the titration curve will start with a pH dependent on the initial concentration of \(\mathrm{B}\), then reach maximum buffering around the \(pK_{\mathrm{a}}\) value, moving on to the stoichiometric point where pH depends on the conjugate acid concentration, and finally, the pH will become dependent on the excess strong acid added.

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Most popular questions from this chapter

Some \(\mathrm{K}_{2} \mathrm{SO}_{3}\) and \(\mathrm{KHSO}_{3}\) are dissolved in 250.0 \(\mathrm{mL}\) of solution and the resulting \(\mathrm{pH}\) is \(7.25 .\) Which is greater in this buffer solution, the concentration of \(\mathrm{SO}_{3}^{2-}\) or the concentration of \(\mathrm{HSO}_{3}-7\) If \(\left[\mathrm{SO}_{3}^{2-}\right]=1.0 \mathrm{M}\) in this solution, calculate the concentration of \(\mathrm{HSO}_{3}\) .

A sample of a certain monoprotic weak acid was dissolved in water and titrated with 0.125\(M \mathrm{NaOH}\) , requiring 16.00 \(\mathrm{mL}\) to reach the equivalence point. During the titration, the pH after adding 2.00 \(\mathrm{mL}\) . NaOH was 6.912 . Calculate \(K_{\mathrm{a}}\) for the weak acid.

When a diprotic acid, \(\mathrm{H}_{2} \mathrm{A},\) is titrated with NaOH, the protons on the diprotic acid are generally removed one at a time, resulting in a pH curve that has the following generic shape: a. Notice that the plot has essentially two titration curves. If the first equivalence point occurs at 100.0 mL NaOH added, what volume of NaOH added corresponds to the second equivalence point? b. For the following volumes of NaOH added, list the major species present after the OH- reacts completely. $$ \begin{array}{l}{\text { i. } 0 \mathrm{mL} \text { NaOH added }} \\ {\text { i. between } 0 \text { and } 100.0 \mathrm{mL} \text { NaOH added }}\end{array} $$ $$ \begin{array}{l}{\text { iii. } 100.0 \text { mL NaOH added }} \\ {\text { iv. between } 100.0 \text { and } 200.0 \mathrm{mL} \text { NaOH added }} \\\ {\text { v. } 200.0 \mathrm{mL} \text { NaOH added }}\end{array} $$ $$ 200.0 \mathrm{mL} $$ c. If the pH at 50.0 \(\mathrm{mL}\) NaOH added is 4.0 and the pH at 150.0 \(\mathrm{mL}\) . NaOH added is \(8.0,\) determine the values \(K_{\mathrm{a}_{1}}\) and \(K_{\mathrm{a}_{2}}\) for the diprotic acid.

Repeat the procedure in Exercise \(67,\) but for the titration of 25.0 \(\mathrm{mL}\) of 0.100\(M\) propanoic acid $\left(\mathrm{HC}_{3} \mathrm{H}_{3} \mathrm{O}_{2}, K_{\mathrm{a}}=1.3 \times 10^{-5}\right)$ with 0.100 \(\mathrm{M} \mathrm{NaOH}\) .

You have a solution of the weak acid HA and add some of the salt NaA to it. What are the major species in the solution? What do you need to know to calculate the pH of the solution, and how would you use this information? How does the pH of the solution of just the HA compare with that of the final mixture? Explain

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