List three different ways to calculate the standard free energy change, \(\Delta G^{\circ},\) for a reaction at \(25^{\circ} \mathrm{C}\) . How is $\Delta G^{\circ}\( estimated at temperatures other than \)25^{\circ} \mathrm{C} ?$ What assumptions are made?

Short Answer

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Three different ways to calculate the standard free energy change, \(\Delta G^{\circ}\), at 25°C are: 1. Using the Gibbs-Helmholtz equation: \(\Delta G^{\circ} = \Delta H^{\circ} - T \Delta S^{\circ}\) 2. Using the equilibrium constant: \(\Delta G^{\circ} = -RT \ln(K)\) 3. Using data tables and the equation: \(\Delta G^{\circ} = \sum \Delta G_f^{\circ}(\text{products}) - \sum \Delta G_f^{\circ}(\text{reactants})\) To estimate \(\Delta G^{\circ}\) at other temperatures, we can use the van't Hoff equation: \[\ln\left(\frac{K_2}{K_1}\right) = -\frac{\Delta H^{\circ}}{R}\left(\frac{1}{T_2} - \frac{1}{T_1}\right)\] Assumptions made while estimating \(\Delta G^{\circ}\) at a different temperature include: 1. The reaction is assumed to be at equilibrium. 2. The standard free energy change, enthalpy change, and entropy change are assumed to be constant over the temperature range being considered. 3. The van't Hoff equation assumes that the change in standard free energy and enthalpy with temperature is negligible.

Step by step solution

01

Method 1: Using Gibbs-Helmholtz equation

The standard free energy change, \(\Delta G^{\circ}\), can be calculated using the Gibbs-Helmholtz equation: \[\Delta G^{\circ} = \Delta H^{\circ} - T \Delta S^{\circ}\] Here, we need to first calculate the standard enthalpy change, \(\Delta H^{\circ}\), and the standard entropy change, \(\Delta S^{\circ}\) of the reaction, then plug them into this equation to calculate the standard free energy change at a given temperature, T (in Kelvin).
02

Method 2: Using equilibrium constant

We can also calculate \(\Delta G^{\circ}\) using the relationship between the equilibrium constant, K, and the standard free energy change: \[\Delta G^{\circ} = -RT \ln(K)\] Here, R is the ideal gas constant (8.314 J/(mol·K)), and T is the temperature (in Kelvin). To use this method, we need to first determine the equilibrium constant, K, for the reaction at the desired temperature, and then plug it into this equation to calculate \(\Delta G^{\circ}\).
03

Method 3: Using the data tables

Another way to calculate \(\Delta G^{\circ}\) is by using the data tables that contain the standard free energy of formation, \(\Delta G_f^{\circ}\), for various substances. The standard free energy change for a reaction can be calculated using the equation: \[\Delta G^{\circ} = \sum \Delta G_f^{\circ}(\text{products}) - \sum \Delta G_f^{\circ}(\text{reactants})\] In this method, we need to look up the standard free energy of formation for each substance involved in the reaction and then use this equation to calculate \(\Delta G^{\circ}\).
04

Estimating \(\Delta G^{\circ}\) at other temperatures

To estimate the standard free energy change at a different temperature, we can use the following van't Hoff equation: \[\ln\left(\frac{K_2}{K_1}\right) = -\frac{\Delta H^{\circ}}{R}\left(\frac{1}{T_2} - \frac{1}{T_1}\right)\] Here, K1 and K2 are the equilibrium constants at the initial (T1) and final (T2) temperatures, respectively. First, we need to determine \(\Delta H^{\circ}\) and K1 for the reaction at the initial temperature using one of the methods mentioned above. Then, we can use this equation to calculate K2 at the desired temperature T2. Finally, we can use the relationship between K and \(\Delta G^{\circ}\) mentioned in Method 2 to calculate the standard free energy change at the new temperature.
05

Assumptions made

There are a few assumptions made while estimating \(\Delta G^{\circ}\) at a different temperature: 1. The reaction is assumed to be at equilibrium. 2. The standard free energy change, enthalpy change, and entropy change are assumed to be constant over the temperature range being considered. 3. The van't Hoff equation assumes that the change in standard free energy and enthalpy with temperature is negligible.

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Most popular questions from this chapter

For the process \(\mathrm{A}(l) \longrightarrow \mathrm{A}(g),\) which direction is favored by changes in energy probability? Positional probability? Explain your answers. If you wanted to favor the process as written, would you raise or lower the temperature of the system? Explain.

Consider the system $$\mathrm{A}(g) \rightleftharpoons \mathrm{B}(g)$$ at \(25^{\circ} \mathrm{C}\) a. Assuming that \(G_{\mathrm{A}}^{\circ}=8996 \mathrm{J} / \mathrm{mol}\) and \(G_{\mathrm{B}}^{\circ}=11,718 \mathrm{J} / \mathrm{mol},\) calculate the value of the equilibrium constant for this reaction. b. Calculate the equilibrium pressures that result if 1.00 mole of \(\mathrm{A}(g)\) at 1.00 atm and 1.00 mole of \(\mathrm{B}(g)\) at 1.00 atm are mixed at \(25^{\circ} \mathrm{C} .\) c. Show by calculations that \(\Delta G=0\) at equilibrium.

Given the following data: $$2 \mathrm{C}_{6} \mathrm{H}_{6}(l)+15 \mathrm{O}_{2}(g) \longrightarrow 12 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l)\Delta G^{\circ}=-6399 \mathrm{kJ}$$ $$\mathrm{C}(s)+\mathrm{o}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) \quad \Delta G^{\circ}=-394 \mathrm{kJ}$$ $$\mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l) \quad \Delta G^{\circ}=-237 \mathrm{kJ}$$ calculate \(\Delta G^{\circ}\) for the reaction $$6 \mathrm{C}(s)+3 \mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{6} \mathrm{H}_{6}(l)$$

Choose the substance with the larger positional probability in each case. a. 1 mole of \(\mathrm{H}_{2}\) (at \(\mathrm{STP} )\) or 1 mole of $\mathrm{H}_{2}\left(\text { at } 100^{\circ} \mathrm{C}, 0.5 \mathrm{atm}\right)$ b. 1 mole of \(\mathrm{N}_{2}(\text { at } \mathrm{STP})\) or 1 mole of \(\mathrm{N}_{2}(\text { at } 100 \mathrm{K}, 2.0 \mathrm{atm})\) c. 1 mole of \(\mathrm{H}_{2} \mathrm{O}(s)\) (at \(0^{\circ} \mathrm{C} )\) or 1 \(\mathrm{mole}\) of $\mathrm{H}_{2} \mathrm{O}(l)\left(\mathrm{at} 20^{\circ} \mathrm{C}\right)$

Which of the following involve an increase in the entropy of the system? a. melting of a solid b. sublimation c. freezing d. mixing e. separation f. boiling

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