What reaction will take place at the cathode and the anode when each of the following is electrolyzed? (Assume standard conditions.) a. 1.0 \(M \mathrm{KF}\) solution b. 1.0\(M \mathrm{CuCl}_{2}\) solution c. 1.0 \( M \mathrm{MgI}_{2}\) solution

Short Answer

Expert verified
For the electrolysis of: a. 1.0 M KF solution: Cathode: \(2H_{2}O + 2e^{-} \rightarrow H_{2} (g) + 2OH^{-}\) ; Anode: \(2H_{2}O \rightarrow O_{2} (g) + 4H^{+} + 4e^{-}\) b. 1.0 M CuCl₂ solution: Cathode: \(Cu^{2+} (aq) + 2e^{-} \rightarrow Cu (s)\) ; Anode: \(2Cl^{-} (aq) \rightarrow Cl_{2} (g) + 2e^{-}\) c. 1.0 M MgI₂ solution: Cathode: \(Mg^{2+} (aq) + 2e^{-} \rightarrow Mg (s)\) ; Anode: \(2I^{-} (aq) \rightarrow I_{2} (s) + 2e^{-}\)

Step by step solution

01

Identify the possible reduction and oxidation half-reactions

We first look at the possible reduction half-reaction happening at the cathode: \(F^{-} (aq) + e^{-} \rightarrow F (s)\) The standard reduction potential is -2.87V. This process would require more energy to reduce the F- to F so it is not feasible. Which means that water will get reduced at the cathode to form hydrogen gas and hydroxide ions: \(2H_{2}O + 2e^{-} \rightarrow H_{2} (g) + 2OH^{-}\) Now let's look at the oxidation half-reaction happening at the anode: \(K(s) \rightarrow K^{+} (aq) + e^{-}\) The potential is -2.93V, meaning it is also not feasible. Instead, water oxidation will occur at the anode: \(2H_{2}O \rightarrow O_{2} (g) + 4H^{+} + 4e^{-}\)
02

Write the overall reaction

Combine the two half-reactions at the cathode and the anode: \(2H_{2}O + 2F^{-} (aq) \rightarrow H_{2} (g) + O_{2} (g) + 2OH^{-} (aq) + 2F^{-} (aq)\) b. Electrolysis of 1.0 M CuCl₂ solution
03

Identify the possible reduction and oxidation half-reactions

Possible reduction half-reaction at the cathode: \(Cu^{2+} (aq) + 2e^{-} \rightarrow Cu (s)\) Possible oxidation half-reactions at the anode: \(2Cl^{-} (aq) \rightarrow Cl_{2} (g) + 2e^{-}\)
04

Write the overall reaction

Combine the two half-reactions at the cathode and the anode: \(Cu^{2+} (aq) + 2Cl^{-} (aq) \rightarrow Cu (s) + Cl_{2} (g)\) c. Electrolysis of 1.0 M MgI₂ solution
05

Identify the possible reduction and oxidation half-reactions

Possible reduction half-reaction at the cathode: \(Mg^{2+} (aq) + 2e^{-} \rightarrow Mg (s)\) Possible oxidation half-reactions at the anode: \(2I^{-} (aq) \rightarrow I_{2} (s) + 2e^{-}\)
06

Write the overall reaction

Combine the two half-reactions at the cathode and the anode: \(Mg^{2+} (aq) + 2I^{-} (aq) \rightarrow Mg (s) + I_{2} (s)\)

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Most popular questions from this chapter

Consider the following galvanic cell: What happens to \(\mathscr{E}\) as the concentration of \(\mathrm{Zn}^{2+}\) is increased? As the concentration of \(\mathrm{Ag}^{+}\) is increased? What happens to \(\mathscr{E}^{\circ}\) in these cases?

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