Consider only the species (at standard conditions) $$$\mathrm{Br}^{-}, \quad \mathrm{Br}_{2}, \quad \mathrm{H}^{+}, \quad \mathrm{H}_{2}, \quad \mathrm{La}^{3+}, \quad \mathrm{Ca}, \quad \mathrm{Cd}$$ in answering the following questions. Give reasons for your answers. a. Which is the strongest oxidizing agent? b. Which is the strongest reducing agent? c. Which species can be oxidized by \(\mathrm{MnO}_{4}^{-}\) in acid? d. Which species can be reduced by \(\mathrm{Zn}(s) ?\)

Short Answer

Expert verified
a) Strongest oxidizing agent: \(\mathrm{Br}_{2}\) b) Strongest reducing agent: \(\mathrm{Ca}\) c) Species that can be oxidized by \(\mathrm{MnO}_{4}^{-}\) in acid: \(\mathrm{H_2}, \mathrm{La}, \mathrm{Ca}, \mathrm{Cd}, \mathrm{Zn}\) d) Species that can be reduced by \(\mathrm{Zn}(s) :\) \(\mathrm{Br}_2, \mathrm{H}_2, \mathrm{Cd}\)

Step by step solution

01

Understanding reduction potentials

Reduction potentials measure the tendency of a chemical species to be reduced or gain electrons. Positive reduction potentials indicate a greater tendency for a species to be reduced, while negative values signify a lower tendency for reduction. In general, species with higher reduction potentials prefer to be reduced, while those with lower reduction potentials prefer to be oxidized.
02

Refer to a standard reduction potential table

The following standard reduction potentials are taken from a standard reduction potential table: \(\mathrm{Br}_2/ \mathrm{Br}^-\): +1.087 V \(\mathrm{H_2/ H}^+\): 0 V \(\mathrm{La^{3+}/La}\): -2.52 V \(\mathrm{Ca/Ca}^{2+}\): -2.87 V \(\mathrm{Cd/Cd}^{2+}\): -0.40 V \(\mathrm{MnO}_4^-/\mathrm{Mn}^{2+}\): +1.51 V (in acidic conditions) \(\mathrm{Zn/Zn}^{2+}\): -0.76 V
03

Identify the strongest oxidizing agent

The strongest oxidizing agent has the highest reduction potential since these species gain electrons most readily. Comparing the reduction potentials listed above, \(\mathrm{Br}_2\) has the highest value of +1.087 V. Therefore, \(\mathrm{Br}_2\) is the strongest oxidizing agent.
04

Identify the strongest reducing agent

The strongest reducing agent has the lowest reduction potential since these species lose electrons most readily. Comparing the reduction potentials listed above, \(\mathrm{Ca}\) has the lowest value of -2.87 V. Therefore, \(\mathrm{Ca}\) is the strongest reducing agent.
05

Identify species that can be oxidized by \(\mathrm{MnO}_{4}^{-}\) in acid

For a reaction to occur, the reduction potential of the oxidizing agent has to be greater than that of the reducing agent. Given that the reduction potential for \(\mathrm{MnO}_4^-\) in acid is +1.51 V, any species with a smaller reduction potential can be oxidized. From the table, the species that can be oxidized are: \(\mathrm{H_2}, \mathrm{La}, \mathrm{Ca}, \mathrm{Cd}, \mathrm{Zn}\)
06

Identify species that can be reduced by \(\mathrm{Zn}(s)\)

For a reaction to occur, the reduction potential of the oxidizing agent has to be greater than that of the reducing agent. Given that the reduction potential for \(\mathrm{Zn}\) is -0.76 V, any species with a larger reduction potential can be reduced. From the table, the species that can be reduced are: \(\mathrm{Br}_2, \mathrm{H_2}, \mathrm{Cd}\) To summarize, the answers to the questions are: a) Strongest oxidizing agent: \(\mathrm{Br}_{2}\) b) Strongest reducing agent: \(\mathrm{Ca}\) c) Species that can be oxidized by \(\mathrm{MnO}_{4}^{-}\) in acid: \(\mathrm{H_2}, \mathrm{La}, \mathrm{Ca}, \mathrm{Cd}, \mathrm{Zn}\) d) Species that can be reduced by \(\mathrm{Zn}(s) :\) \(\mathrm{Br}_2, \mathrm{H}_2, \mathrm{Cd}\)

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Most popular questions from this chapter

Three electrochemical cells were connected in series so that the same quantity of electrical current passes through all three cells. In the first cell, 1.15 g chromium metal was deposited from a chromium (III) nitrate solution. In the second cell, 3.15 \(\mathrm{g}\) osmium was deposited from a solution made of \(\mathrm{Os}^{n+}\) and nitrate ions. What is the name of the salt? In the third cell, the electrical charge passed through a solution containing \(\mathrm{X}^{2+}\) ions caused deposition of 2.11 \(\mathrm{g}\) metallic \(\mathrm{X}\) . What is the electron configuration of \(\mathrm{X} ?\)

Consider the following galvanic cell: What happens to \(\mathscr{E}\) as the concentration of \(\mathrm{Zn}^{2+}\) is increased? As the concentration of \(\mathrm{Ag}^{+}\) is increased? What happens to \(\mathscr{E}^{\circ}\) in these cases?

Define oxidation and reduction in terms of both change in oxidation number and electron loss or gain.

You have a concentration cell in which the cathode has a silver electrode with 0.10\(M \mathrm{Ag}^{+} .\) The anode also has a silver electrode with \(\mathrm{Ag}^{+}(a q), 0.050 M \mathrm{S}_{2} \mathrm{O}_{3}^{2-},\) and $1.0 \times 10^{-3} M\( \)\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}^{3-}\( . You read the voltage to be 0.76 \)\mathrm{V}$ . a. Calculate the concentration of \(\mathrm{Ag}^{+}\) at the anode. b. Determine the value of the equilibrium constant for the formation of \(\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}^{3-}\). $$\mathrm{Ag}^{+}(a q)+2 \mathrm{S}_{2} \mathrm{O}_{3}^{2-}(a q) \rightleftharpoons \mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}^{3-}(a q) \quad K=?$$

The overall reaction in the lead storage battery is $\mathrm{Pb}(s)+\mathrm{PbO}_{2}(s)+2 \mathrm{H}^{+}(a q)+2 \mathrm{HSO}_{4}^{-}(a q) \longrightarrow$ \(2 \mathrm{PbSO}_{4}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)\) Calculate \(\mathscr{E}\) at \(25^{\circ} \mathrm{C}\) for this battery when \(\left[\mathrm{H}_{2} \mathrm{SO}_{4}\right]=4.5 \mathrm{M}\), that is, $\left[\mathrm{H}^{+}\right]=\left[\mathrm{HSO}_{4}^{-}\right]=4.5 \mathrm{M} . \mathrm{At} 25^{\circ} \mathrm{C}, \mathscr{E}^{\circ}=2.04 \mathrm{V}$ for the lead storage battery.

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