Write an equation describing the radioactive decay of each of the following nuclides. (The particle produced is shown in parentheses, except for electron capture, where an electron is a reactant.) a.\(_{1}^{3} \mathrm{H}(\beta)\) b. \(_{3}^{8} \operatorname{Li}(\beta \text { followed by } \alpha)\) c. \(\quad_{4}^{7}\) Be (electron capture) d. \(_{5}^{8} \mathrm{B}(\text { positron })\)

Short Answer

Expert verified
The short version of the answer for each nuclide radioactive decay is: a. \[_{1}^{3} \mathrm{H} \to _{2}^{3} \mathrm{He} + \beta^{-} + \bar{\nu}_e\] b. \[_{3}^{8} \operatorname{Li} \to _{4}^{8} \mathrm{Be} + \beta^{-} + \bar{\nu}_e\] _ \[_{4}^{8} \mathrm{Be} \to _{2}^{4} \mathrm{He} + _{2}^{4} \mathrm{He}\] c. \[_{4}^{7} \mathrm{Be} + e^{-} \to _{3}^{7} \mathrm{Li} + \nu_e\] d. \[_{5}^{8} \mathrm{B} \to _{4}^{8} \mathrm{Be} + \beta^{+} + \nu_e\]

Step by step solution

01

Identify the initial nuclide and decay process

For this problem, we have Hydrogen-3 undergoing beta (β) decay. In a beta decay, the initial nuclide emits an electron (β-) and an antineutrino, converting a neutron to a proton.
02

Write the equation for the decay process

We will write the equation as follows: \[_{1}^{3} \mathrm{H} \to _{2}^{3} \mathrm{He} + \beta^{-} + \bar{\nu}_e\] #b. Beta decay followed by alpha decay of Lithium-8#
03

Recognize the initial nuclide and decay processes

For this decay, we have Lithium-8 undergoing beta (β) decay followed by alpha (α) decay. We'll handle these two decay processes separately.
04

Write the equation for the beta decay process

The initial nuclide emits an electron (β-) and an antineutrino, converting a neutron to a proton: \[_{3}^{8} \operatorname{Li} \to _{4}^{8} \mathrm{Be} + \beta^{-} + \bar{\nu}_e\]
05

Write the equation for the alpha decay process

After the beta decay, the produced Beryllium-8 undergoes an alpha decay, during which an alpha particle (Helium-4 nucleus) is emitted. \[_{4}^{8} \mathrm{Be} \to _{2}^{4} \mathrm{He} + _{2}^{4} \mathrm{He}\] #c. Electron capture of Beryllium-7#
06

Identify the initial nuclide and decay process

The initial nuclide is Beryllium-7, which undergoes electron capture. In electron capture, an inner-shell electron is captured by the nucleus and combines with a proton to form a neutron. This process also emits a neutrino.
07

Write the equation for the electron capture process

We will write the equation as follows: \[_{4}^{7} \mathrm{Be} + e^{-} \to _{3}^{7} \mathrm{Li} + \nu_e\] #d. Positron decay of Boron-8#
08

Identify the initial nuclide and decay process

The initial nuclide is Boron-8, which undergoes positron decay. In positron decay, the nucleus emits a positron (β+), i.e., an anti-electron, which converts a proton into a neutron. This process also emits a neutrino.
09

Write the equation for the positron decay process

We will write the equation as follows: \[_{5}^{8} \mathrm{B} \to _{4}^{8} \mathrm{Be} + \beta^{+} + \nu_e\]

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