The rate constant for a certain radioactive nuclide is $1.0 \times 10^{-3} \mathrm{h}^{-1} .$ What is the half-life of this nuclide?

Short Answer

Expert verified
The half-life (T) of the radioactive nuclide can be found using the formula \(T = \frac{\ln(2)}{k}\), where k is the rate constant. Given the rate constant \(k = 1.0 \times 10^{-3} h^{-1}\), the half-life of the nuclide is approximately \(T = \frac{\ln(2)}{1.0 \times 10^{-3} h^{-1}} \approx 693\) hours.

Step by step solution

01

1. Write down the given information and formula.

We are given the rate constant (k) for a certain radioactive nuclide: \(k = 1.0 \times 10^{-3} h^{-1}\). We want to find the half-life (T) of this nuclide. The formula connecting these values is: \(T = \frac{\ln(2)}{k}\)
02

2. Substitute the rate constant into the formula.

Now we can plug in the value of the rate constant k into the formula: \(T = \frac{\ln(2)}{1.0 \times 10^{-3} h^{-1}}\)
03

3. Calculate the half-life (T).

Divide the natural logarithm of 2 by the rate constant to find the half-life of the nuclide: \(T = \frac{\ln(2)}{1.0 \times 10^{-3} h^{-1}} \approx \frac{0.693}{1.0 \times 10^{-3} h^{-1}} = 693 \, hours\)
04

4. State the final answer.

The half-life of this radioactive nuclide is approximately 693 hours.

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