In addition to the process described in the text, a second process called the carbon-nitrogen cycle occurs in the sun: a. What is the catalyst in this process? b. What nucleons are intermediates? c. How much energy is released per mole of hydrogen nuclei in the overall reaction? (The atomic masses of \(_{1}^{1} \mathrm{H}\) and $\frac{4}{2} \mathrm{He}\( are 1.00782 \)\mathrm{u}\( and \)4.00260 \mathrm{u},$ respectively.)

Short Answer

Expert verified
a. The catalyst in the carbon-nitrogen cycle is carbon. b. The intermediate nucleons in the carbon-nitrogen cycle are Nitrogen-13, Carbon-12, Carbon-13, Nitrogen-14, and Oxygen-15. c. The energy released per mole of hydrogen nuclei in the overall carbon-nitrogen cycle reaction is approximately 2.95 x 10^12 Joules/mol.

Step by step solution

01

Understanding the carbon-nitrogen cycle

The carbon-nitrogen (C-N) cycle is a set of fusion reactions by which stars convert hydrogen into helium, the primary alternative being the proton-proton chain. The C-N cycle involves heavier catalyst elements like carbon and nitrogen as intermediates for it to occur.
02

Identifying the catalyst in the process

The catalyst in the carbon-nitrogen cycle is carbon. Carbon plays an essential role in transforming hydrogen nuclei into helium through a series of reactions involving nitrogen and other intermediate elements.
03

Identifying the intermediate nucleons

The intermediate nucleons in the carbon-nitrogen cycle include: - Nitrogen-13 (\(_{7}^{13}\mathrm{N}\)) - Carbon-12 (\(_{6}^{12}\mathrm{C}\)) - Carbon-13 (\(_{6}^{13}\mathrm{C}\)) - Nitrogen-14 (\(_{7}^{14}\mathrm{N}\)) - Oxygen-15 (\(_{8}^{15}\mathrm{O}\)) These intermediate nuclei help to transform four hydrogen nuclei into one helium nucleus.
04

Calculating the energy released per mole of hydrogen nuclei

To calculate the amount of energy released per mole of hydrogen nuclei in the overall reaction, we need to determine the mass difference between the reactants and products. The overall reaction involves the transformation of four hydrogen nuclei into one helium nucleus: \[4_{1}^{1}\mathrm{H} \rightarrow 4 \mathrm{He}\] Now, we calculate the mass difference: Mass difference = (Mass of four hydrogen nuclei) - (Mass of one helium nucleus) Using the given atomic masses: Mass of four hydrogen nuclei = 4 * 1.00782 u Mass of one helium nucleus = 4.00260 u Mass difference = (4 * 1.00782 u) - 4.00260 u Mass difference = 0.03128 u To convert this mass difference into energy, we use the famous Einstein's mass-energy equivalence equation, E=mc^2, and the following conversion factors: 1 u = 1.66 x 10^{-27} kg c = 3.00 x 10^8 m/s (speed of light) Energy released = (Mass difference) * (1.66 x 10^{-27} kg/u) * (3.00 x 10^8 m/s)^2 Energy released = 4.894 x 10^{-12} J (per nucleus) 1 mole = 6.022 x 10^23 nuclei Energy released per mole = (4.894 x 10^{-12} J) * (6.022 x 10^23 nuclei/mol) Energy released per mole ≈ 2.95 x 10^12 J/mol Hence, the energy released per mole of hydrogen nuclei in the overall carbon-nitrogen cycle reaction is approximately 2.95 x 10^12 Joules/mol.

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