An element's most stable ion forms an ionic compound with bromine, having the formula \(\mathrm{XBr}_{2}\) . If the ion of element \(\mathrm{X}\) has a mass number of 230 and has 86 electrons, what is the identity of the element, and how many neutrons does it have?

Short Answer

Expert verified
The element X is radium (Ra) with an atomic number of 88, and it has 142 neutrons in its nucleus.

Step by step solution

01

Determine the charge of element X

Since the compound formed is XBr2, it means that one ion of element X combines with two ions of bromine (Br) to achieve electrical neutrality. Bromine has an atomic number of 35, which means it has 35 protons and 35 electrons in a neutral atom. When bromine forms an ion (Br-), it gains one electron to achieve a full outer electron shell, making it have 36 electrons. We can find the charge on the ion of element X: Ionic compound: XBr2 Total bromine charge: 2 * (-1) = -2 The combined charges must equal zero to achieve electrical neutrality, so the charge on the ion of element X must be +2.
02

Determine the atomic number of element X

Since the ion of element X has a charge of +2, it means that it has lost two electrons to achieve a full outer electron shell. The neutral atom of element X has the same number of electrons as protons. Given that the ion has 86 electrons, the neutral atom must have 88 electrons. Thus, the atomic number of element X is 88.
03

Identify the element X

Using the Periodic Table, we can identify the element with an atomic number of 88, which is radium (Ra).
04

Calculate the number of neutrons in element X

We know the mass number of element X is 230, and the atomic number is 88. The mass number is the sum of the protons and neutrons in the nucleus of the atom. We can find the number of neutrons in element X using the following equation: Number of neutrons = Mass number - Atomic number Number of neutrons = 230 - 88 Number of neutrons = 142 The identity of element X is radium (Ra), and it has 142 neutrons.

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