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Chapter 2: Problem 51

In an experiment it was found that the total charge on an oil drop was $5.93 \times 10^{-18} \mathrm{C}$ . How many negative charges does the drop contain?

Short Answer

Expert verified
The oil drop contains approximately 37 negative charges (electrons).

Step by step solution

01

Identify the given information

We are provided with the total charge on the oil drop: \(Q = 5.93 \times 10^{-18} \mathrm{C}\). We also know the fundamental charge of an electron: \(e = -1.6 \times 10^{-19} \mathrm{C}\).
02

Determine the number of electrons needed for the net charge

To determine the number of electrons on the oil drop, we will take the total charge (Q) and divide it by the charge of one electron (e). The formula is: \[n = \frac{Q}{e}\]
03

Calculate the number of electrons on the oil drop

Plugging the given values into the formula, we get: \[n = \frac{5.93 \times 10^{-18} \mathrm{C}}{-1.6 \times 10^{-19} \mathrm{C}}\]
04

Simplify the equation and find the result

By dividing the values of the charges, we get the number of electrons: \[n \approx 37.06\] Since the number of electrons must be a whole number, we round to the nearest whole number: \[n \approx 37\] So, the oil drop contains approximately 37 negative charges (electrons).

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Most popular questions from this chapter

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