For each of the following ions, indicate the number of protons and electrons the ion contains. a. \(\quad \mathrm{Ba}^{2+}\) b. \(\mathrm{Zn}^{2+}\) c. \(\mathrm{N}^{3-}\) d. \(\mathrm{Rb}^{+}\) e. \(\mathrm{Co}^{3+}\) f. \(\mathrm{Te}^{2-}\) g. \(\mathrm{Br}^{-}\)

To determine the number of protons in the different elements, consult the periodic table. Next to each element's symbol, you will find the atomic number (whole number), which represents the number of protons in an atom of that element.

To determine the number of protons and electrons in each ion, consider the charge of the ion. The charge of the ion indicates how many electrons have been added or removed from a neutral atom. If the charge is positive, that means electrons are removed, and if the charge is negative, it means electrons are added. a. For \(\mathrm{Ba}^{2+}\), the atomic number of Ba (Barium) is 56, so: - Protons: 56 - Electrons: 56 - 2 = 54 b. For \(\mathrm{Zn}^{2+}\), the atomic number of Zn (Zinc) is 30, so: - Protons: 30 - Electrons: 30 - 2 = 28 c. For \(\mathrm{N}^{3-}\), the atomic number of N (Nitrogen) is 7, so: - Protons: 7 - Electrons: 7 + 3 = 10 d. For \(\mathrm{Rb}^{+}\), the atomic number of Rb (Rubidium) is 37, so: - Protons: 37 - Electrons: 37 - 1 = 36 e. For \(\mathrm{Co}^{3+}\), the atomic number of Co (Cobalt) is 27, so: - Protons: 27 - Electrons: 27 - 3 = 24 f. For \(\mathrm{Te}^{2-}\), the atomic number of Te (Tellurium) is 52, so: - Protons: 52 - Electrons: 52 + 2 = 54 g. For \(\mathrm{Br}^{-}\), the atomic number of Br (Bromine) is 35, so: - Protons: 35 - Electrons: 35 + 1 = 36