Would you expect each of the following atoms to gain or lose electrons when forming ions? What ion is the most likely in each case? a. Ra b. In c. P d. Te e. Br f. Rb

Short Answer

Expert verified
Ra will likely form a Ra^(2+) ion, In will form an In^(3+) ion, P will form a P^(3-) ion, Te will form a Te^(2-) ion, Br will form a Br^(-) ion, and Rb will form an Rb^(1+) ion.

Step by step solution

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a. Ra (Radium)

Radium is in group 2 of the periodic table, belonging to the alkaline earth metals. Elements in group 2 have a general electron configuration of [noble gas] ns^2. They tend to lose two electrons to achieve a stable electron configuration, forming ions with a 2+ charge. So, Ra will most likely form a Ra^(2+) ion.
02

b. In (Indium)

Indium is in group 13 of the periodic table. Elements in group 13 have a general electron configuration of [noble gas] ns^2 np^1. These elements tend to lose three electrons to achieve a stable electron configuration, forming ions with a 3+ charge. So, In will most likely form an In^(3+) ion.
03

c. P (Phosphorus)

Phosphorus is in group 15 of the periodic table. Elements in this group have a general electron configuration of [noble gas] ns^2 np^3. They tend to gain three electrons to achieve a stable electron configuration, forming ions with a 3- charge. So, P will most likely form a P^(3-) ion.
04

d. Te (Tellurium)

Tellurium is in group 16 of the periodic table, which includes the chalcogens. Elements in this group have a general electron configuration of [noble gas] ns^2 np^4. They tend to gain two electrons to achieve a stable electron configuration, forming ions with a 2- charge. So, Te will most likely form a Te^(2-) ion.
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e. Br (Bromine)

Bromine is in group 17 of the periodic table, which includes the halogens. Elements in this group have a general electron configuration of [noble gas] ns^2 np^5. They tend to gain one electron to achieve a stable electron configuration, forming ions with a 1- charge. So, Br will most likely form a Br^(-) ion.
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f. Rb (Rubidium)

Rubidium is in group 1 of the periodic table, belonging to the alkali metals. Elements in group 1 have a general electron configuration of [noble gas] ns^1. They tend to lose one electron to achieve a stable electron configuration, forming ions with a 1+ charge. So, Rb will most likely form an Rb^(1+) ion.

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