Name each of the following compounds: a. \(\mathrm{CsF}\) b. b. \(\mathrm{Li}_{3} \mathrm{N}\) c. \(\mathrm{Ag}_{2} \mathrm{S}\) d. \(\mathrm{MnO}_{2}\) e. \(\mathrm{TiO}_{2}\) f. \(\mathrm{Sr}_{3} \mathrm{P}_{2}\)

Short Answer

Expert verified
a. Cesium Fluoride b. Lithium Nitride c. Silver Sulfide d. Manganese(IV) Oxide e. Titanium(IV) Oxide f. Strontium Phosphide

Step by step solution

01

a. Naming CsF

Cs is Cesium and F is Fluorine. In an ionic compound, the metal (Cesium) is written first, followed by the non-metal (Fluorine). The non-metal's name gets slightly modified by adding the suffix "-ide," resulting in Fluoride. So, the compound's name is Cesium Fluoride.
02

b. Naming Li3N

Li is Lithium and N is Nitrogen. Following the same rules as above, the compound is named Lithium Nitride.
03

c. Naming Ag2S

Ag is Silver and S is Sulfur. Silver is a transition metal that typically forms a +1 ion, so there is no need to mention its charge. Thus, the compound is named Silver Sulfide.
04

d. Naming MnO2

Mn is Manganese and O is Oxygen. As Manganese is a transition metal, we must indicate the charge, or oxidation number, with a Roman numeral. Since each Oxygen atom has a charge of -2 and there are two Oxygen atoms, the Manganese must have a +4 charge. The compound is named Manganese(IV) Oxide.
05

e. Naming TiO2

Ti is Titanium and O is Oxygen. Titanium is also a transition metal, so we must indicate its charge. In this case, the two Oxygen atoms have a combined charge of -4, so the Titanium must have a +4 charge. The compound is named Titanium(IV) Oxide.
06

f. Naming Sr3P2

Sr is Strontium and P is Phosphorus. Here, Strontium is the metal and Phosphorus is the non-metal. The name of the non-metal element Phosphorus becomes Phosphide. The compound is named Strontium Phosphide.

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