Name each of the following compounds: a. \(\mathrm{BaSO}_{3}\) b. \(\mathrm{NaNO}_{2}\) c. \(\mathrm{KMnO}_{4}\) d. \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)

Short Answer

Expert verified
The short answer is: a. Barium Sulfite (\(\mathrm{BaSO}_{3}\)) b. Sodium Nitrite (\(\mathrm{NaNO}_{2}\)) c. Potassium Permanganate (\(\mathrm{KMnO}_{4}\)) d. Potassium Dichromate (\(\mathrm{K}_{2}\mathrm{Cr}_{2}\mathrm{O}_{7}\))

Step by step solution

01

a. Naming BaSO3

We have Barium \((\mathrm{Ba})\), Sulfur \((\mathrm{S})\), and Oxygen \((\mathrm{O})\) with the subscript "3" for the Oxygen atoms. This compound is an ionic compound, and its name is based on the cation (which is Barium) and the anion (which is derived from Sulfur and Oxygen). Here, \(\mathrm{S}\) and \(\mathrm{O}\) form a polyatomic anion called Sulfite, with a chemical formula of \(\mathrm{SO}_{3}^{2-}\). Hence, we get the name Barium Sulfite for the compound \(\mathrm{BaSO}_{3}\).
02

b. Naming NaNO2

We have Sodium \((\mathrm{Na})\), Nitrogen \((\mathrm{N})\), and Oxygen \((\mathrm{O})\) with the subscript "2" for the Oxygen atoms. This compound is also an ionic compound, and its name is based on the cation (Sodium) and the anion (which is derived from Nitrogen and Oxygen). Here, \(\mathrm{N}\) and \(\mathrm{O}\) form a polyatomic anion called Nitrite, with a chemical formula of \(\mathrm{NO}_{2}^{-}\). Hence, we get the name Sodium Nitrite for the compound \(\mathrm{NaNO}_{2}\).
03

c. Naming KMnO4

We have Potassium \((\mathrm{K})\), Manganese \((\mathrm{Mn})\), and Oxygen \((\mathrm{O})\) with the subscript "4" for the Oxygen atoms. Again, this is an ionic compound whose name is based on the cation (Potassium) and the anion (which is derived from Manganese and Oxygen). Here, \(\mathrm{Mn}\) and \(\mathrm{O}\) form a polyatomic anion called Permanganate, with a chemical formula of \(\mathrm{MnO}_{4}^{-}\). Hence, we get the name Potassium Permanganate for the compound \(\mathrm{KMnO}_{4}\).
04

d. Naming K2Cr2O7

We have Potassium \((\mathrm{K})\) with a subscript "2," Chromium \((\mathrm{Cr})\) with a subscript "2," and Oxygen \((\mathrm{O})\) with a subscript "7." In this ionic compound, we have the cation as Potassium (having two potassium ions) and the anion formed with Chromium and Oxygen. Here, \(\mathrm{Cr}\) and \(\mathrm{O}\) form a polyatomic anion called Dichromate, with a chemical formula of \(\mathrm{Cr}_{2}\mathrm{O}_{7}^{2-}\). Hence, we get the name Potassium Dichromate for the compound \(\mathrm{K}_{2}\mathrm{Cr}_{2}\mathrm{O}_{7}\).

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Most popular questions from this chapter

A sample of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) contains 2.02 \(\mathrm{g}\) of hydrogen, 32.07 \(\mathrm{g}\) of sulfur, and 64.00 \(\mathrm{g}\) of oxygen. How many grams of sulfur and grams of oxygen are present in a second sample of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) containing 7.27 \(\mathrm{g}\) of hydrogen?

The designations 1A through 8A used for certain families of the periodic table are helpful for predicting the charges on ions in binary ionic compounds. In these compounds, the metals generally take on a positive charge equal to the family number, while the nonmetals take on a negative charge equal to the family number minus eight. Thus the compound between sodium and chlorine contains \(\mathrm{Na}^{+}\) ions and \(\mathrm{Cl}^{-}\) ions and has the formula NaCl. Predict the formula and the name of the binary compound formed from the following pairs of elements. a. Ca and N b. \(\mathrm{K}\) and \(\mathrm{O}\) c. \(\mathrm{Rb}\) and \(\mathrm{F}\) d. Mg and S e. Ba and I f. Al and Se g. \(\mathrm{Cs}\) and \(\mathrm{P}\) h. In and Br

Reaction of 2.0 \(\mathrm{L}\) of hydrogen gas with 1.0 \(\mathrm{L}\) of oxygen gas yields 2.0 \(\mathrm{L}\) of water vapor. All gases are at the same temperature and pressure. Show how these data support the idea that oxygen gas is a diatomic molecule. Must we consider hydrogen to be a diatomic molecule to explain these results?

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