In addition to \(\mathrm{CO}_{2},\) two additional stable oxides of carbon \ form. The space-filling models for \(\mathrm{CO}_{2}\) and the other two stable oxides are: What are the formulas for the two additional stable oxides of carbon? Explain the bonding in each of these two forms using the localized electron model.

Short Answer

Expert verified
The two additional stable oxides of carbon are carbon monoxide (CO) and carbon suboxide (C3O2). In CO, a triple bond forms between carbon and oxygen, with one lone pair on carbon and two lone pairs on oxygen. In C3O2, the first two carbon atoms form a double bond with a single oxygen atom and a single bond with another carbon atom, and the third carbon atom forms a single bond with the other oxygen atom. There is one lone pair on the first two carbon atoms, two lone pairs on the third carbon atom, and two lone pairs on each oxygen atom.

Step by step solution

01

Identify the formulas of two additional oxides of carbon

The three stable oxides of carbon are carbon dioxide (CO2), carbon monoxide (CO), and carbon suboxide (C3O2).
02

Explain bonding in CO using the localized electron model

In carbon monoxide (CO), carbon has 4 valence electrons, and oxygen has 6 valence electrons. According to the localized electron model: 1. Carbon forms a triple bond with oxygen, which means that there are 6 bonding electrons shared between carbon and oxygen. 2. Each atom also has a pair of non-bonding electrons. Carbon has one lone pair (2 non-bonding electrons), and oxygen has two lone pairs (4 non-bonding electrons). Therefore, the localized electron model for CO is a triple bond between carbon and oxygen, with one lone pair on the carbon atom and two lone pairs on the oxygen atom.
03

Explain bonding in C3O2 using the localized electron model

In carbon suboxide (C3O2), there are 3 carbon atoms and 2 oxygen atoms. Each carbon atom has 4 valence electrons, and each oxygen atom has 6 valence electrons. According to the localized electron model: 1. Two carbon atoms form a double bond with a single oxygen atom. This means that there are 4 bonding electrons shared between the carbon and oxygen atoms. 2. The remaining carbon atom forms a single bond with the other oxygen atom, meaning there are 2 bonding electrons shared between this carbon and oxygen atom. 3. The first two carbon atoms each have one lone pair (2 non-bonding electrons). 4. The third carbon atom has two lone pairs (4 non-bonding electrons). 5. Each oxygen atom also has two lone pairs (4 non-bonding electrons). Therefore, the localized electron model for C3O2 is: - A double bond between the first carbon atom and an oxygen atom, with a single bond connecting to the second carbon atom and double bond with the other oxygen atom. - A single bond between the third carbon atom and the other oxygen atom. - One lone pair on the first two carbon atoms, two lone pairs on the third carbon atom, and two lone pairs on each oxygen atom.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Slaked lime, \(\mathrm{Ca}(\mathrm{OH})_{2},\) is used to soften hard water by removing calcium ions from hard water through the reaction $$ \begin{array}{r}{\mathrm{Ca}(\mathrm{OH})_{2}(a q)+\mathrm{Ca}^{2+}(a q)+2 \mathrm{HCO}_{3}^{-}(a q) \rightarrow} \\ {2 \mathrm{CaCO}_{3}(s)+2 \mathrm{H}_{2} \mathrm{O}(l)}\end{array} $$ Although \(\mathrm{CaCO}_{3}(s)\) is considered insoluble, some of it does dissolve in aqueous solutions. Calculate the molar solubility of \(\mathrm{CaCO}_{3}\) in water $\left(K_{\mathrm{sp}}=8.7 \times 10^{-9}\right) .$

Silicon is produced for the chemical and electronics industries by the following reactions. Give the balanced equation for each reaction. a. $\operatorname{Si} \mathrm{O}_{2}(s)+\mathrm{C}(s) \longrightarrow \mathrm{Si}(s)+\mathrm{CO}(g)$ b. Silicon tetrachloride is reacted with very pure magne- sium, producing silicon and magnesium chloride. c. $\mathrm{Na}_{2} \mathrm{SiF}_{6}(s)+\mathrm{Na}(s) \longrightarrow \mathrm{Si (s)+\mathrm{NaF}(s)$

Nitrous oxide \(\left(\mathrm{N}_{2} \mathrm{O}\right)\) can be produced by thermal decomposition of ammonium nitrate: $$ \mathrm{NH}_{4} \mathrm{NO}_{3}(s) \stackrel{\mathrm{heat}}{\longrightarrow} \mathrm{N}_{2} \mathrm{O}(g)+2 \mathrm{H}_{2} \mathrm{O}(l) $$ What volume of \(\mathrm{N}_{2} \mathrm{O}(g)\) collected over water at a total pressure of 94.0 \(\mathrm{kPa}\) and \(22^{\circ} \mathrm{C}\) can be produced from thermal decomposition of 8.68 $\mathrm{g} \mathrm{NH}_{4} \mathrm{NO}_{3} ?\( The vapor pressure of water at \)22^{\circ} \mathrm{C}$ is 21 torr.

Write a balanced equation describing the reaction of aluminum metal with concentrated aqueous sodium hydroxide.

In most compounds, the solid phase is denser than the liquid phase. Why isn't this true for water?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free