How does the oxyacid strength of the halogens vary as the number of oxygens in the formula increases?

Short Answer

Expert verified
The strength of oxyacids of halogens increases as the number of oxygen atoms in the formula increases. This occurs because additional oxygen atoms make the O-H bond more polar, facilitating the donation of an H+ ion, and also stabilize the conjugate base by delocalizing the negative charge over the multiple oxygen atoms attached to the central halogen atom.

Step by step solution

01

- Understanding Acid Strength

Acid strength is determined by the ability of the acid to donate a proton (H+) and the stability of its conjugate base. An acid is stronger when it easily donates the H+ ion and results in a stable conjugate base.
02

- Role of Oxygen in an Oxyacid

In an oxyacid, a halogen (X) is attached to an oxygen atom, and the oxygen atom is also attached to a Hydrogen atom (making an OH bond). When an oxyacid donates a proton (steps to behave as an acid), it's the Hydrogen atom connected to an Oxygen atom that is given.
03

- Increasing the Number of Oxygen Atoms

If the number of oxygen atoms in the formula increases, these additional oxygen atoms will also be linked to the halogen atom. These oxygen atoms are highly electronegative which means they draw electron density towards themselves. This makes the O-H bond more polar and makes it easier to donate the H+ ion, thus increasing the acid strength.
04

- The Stability of the Conjugate Base

The additional oxygen atoms do not only improve the ability to donate an H+ ion, but they also stabilise the conjugate base. After the H+ ion is given away, a negative charge is left on the oxygen atom. That negative charge can be spread (delocalized) over the multiple oxygen atoms attached to the central Halogen atom. As a result, it stabilizes the negative charge on the conjugate base, thus making the acid stronger. Hence, as we increase the number of oxygen atoms in the formula of the oxyacid of a halogen, the strength of the acid increases.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following statement(s) is(are) true? a. The alkali metals are found in the earth’s crust in the form of pure elements. b. Gallium has one of the highest melting points known for metals. c. When calcium metal reacts with water, one of the products is \(\mathrm{H}_{2}(g) .\) d. When AlCl \(_{3}\) is dissolved in water, it produces an acidic solution. e. Lithium reacts in the presence of excess oxygen gas to form lithium superoxide.

Argon gas is inert, so it poses no serious health risks. However, if significant amounts of radon are inhaled into the lungs, lung cancer is a possible result. Explain the health risk differences between argon gas and radon gas.

The inert-pair effect is sometimes used to explain the tendency of heavier members of Group 3 \(\mathrm{A}\) to exhibit \(+1\) and \(+3\) oxidation states. What does the inert-pair effect reference? (Hint:Consider the valence electron configuration for Group 3 \(\mathrm{A}\) elements.)

Write equations describing the reactions of Sn with each of the following: \(\mathrm{Cl}_{2}, \mathrm{O}_{2},\) and \(\mathrm{HCl}\) .

Hydrogen is produced commercially by the reaction of methane with steam: $$ \mathrm{CH}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}(g)+3 \mathrm{H}_{2}(g) $$ a. Calculate \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) for this reaction (use the data in Appendix 4\()\) b. What temperatures will favor product formation at standard conditions? Assume \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not depend on temperature.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free