Sulfur forms a wide variety of compounds in which it has \(+6\) \(+4,+2,0,\) and \(-2\) oxidation states. Give examples of sulfur compounds having each of these oxidation states.

Short Answer

Expert verified
Examples of sulfur compounds with the specified oxidation states are as follows: 1. +6 oxidation state: Sulfuric acid (H2SO4) 2. +4 oxidation state: Sulfur dioxide (SO2) 3. +2 oxidation state: Hydrogen sulfite ion (HSO3^-) 4. 0 oxidation state: Elemental sulfur (S8) 5. -2 oxidation state: Hydrogen sulfide (H2S)

Step by step solution

01

Example of Sulfur in +6 Oxidation State

One example of a sulfur compound with a +6 oxidation state is sulfuric acid (H2SO4). In this compound, sulfur is bonded to four oxygen atoms and has an oxidation state of +6.
02

Example of Sulfur in +4 Oxidation State

One example of a sulfur compound with a +4 oxidation state is sulfur dioxide (SO2). In this compound, sulfur is bonded to two oxygen atoms and has an oxidation state of +4.
03

Example of Sulfur in +2 Oxidation State

One example of a sulfur compound with a +2 oxidation state is hydrogen sulfite ion (HSO3^-). In this ion, sulfur is bonded to three oxygen atoms and one hydrogen atom. The sulfur atom has an oxidation state of +2.
04

Example of Sulfur in 0 Oxidation State

One example of a sulfur compound with a 0 oxidation state is elemental sulfur (S8). In this compound, sulfur exists as a ring of eight sulfur atoms where each sulfur atom is bonded to two other sulfur atoms. The sulfur atoms have an oxidation state of 0.
05

Example of Sulfur in -2 Oxidation State

One example of a sulfur compound with a -2 oxidation state is hydrogen sulfide (H2S). In this compound, sulfur is bonded to two hydrogen atoms and has an oxidation state of -2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What trade-offs must be made between kinetics and thermodynamics in the Haber process for the production of ammonia? How did the discovery of an appropriate catalyst make the process feasible?

For each of the following, write the Lewis structure(s), predict the molecular structure (including bond angles), and give the expected hybridization of the central atom. a. \(\mathrm{KrF}_{2} \quad\) b. \(\mathrm{KrF}_{4} \quad\) c. $\mathrm{XeO}_{2} \mathrm{F}_{2} \quad\( d. \)\mathrm{XeO}_{2} \mathrm{F}_{4}$

Use the symbols of the elements described in the following clues to fill in the blanks that spell out the name of a famous American scientist. Although this scientist was better known as a physicist than as a chemist, the Philadelphia institute that bears his name does include a biochemistry research facility. (1) The oxide of this alkaline earth metal is amphoteric. (2) The element that makes up approximately 3.0% by mass of the human body. (3) The element having a 7\(s^{1}\) valence electron configuration. (4) This element is the alkali metal with the least negative standard reduction potential. Write its symbol in reverse order. (5) The alkali metal whose ion is more concentrated in intracellular fluids as compared with blood plasma. (6) This is the only alkali metal that reacts directly with nitrogen to make a binary compound with formula \(\mathrm{M}_{3} \mathrm{N}\). (7) This element is the first in Group 3A for which the 11 oxidation state is exhibited in stable compounds. Use only the second letter of its symbol.

Lead forms compounds in the \(+2\) and \(+4\) oxidation states. All lead(II) halides are known (and are known to be ionic). Only \(\mathrm{PbF}_{4}\) and \(\mathrm{PbCl}_{4}\) are known among the possible lead(IV) halides. Presumably lead(IV) oxidizes bromide and iodide ions, producing the lead(Il) halide and the free halogen: $$ \mathrm{PbX}_{4} \longrightarrow \mathrm{PbX}_{2}+\mathrm{X}_{2} $$ Suppose 25.00 g of a lead(IV) halide reacts to form 16.12 g of a lead(Il) halide and the free halogen. Identify the halogen.

All the Group 1 \(\mathrm{A}\) and 2 \(\mathrm{A}\) metals are produced by electrolysis of molten salts. Why?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free