Which of the following ligands are capable of linkage isomerism? Explain your answer. $$\mathrm{SCN}^{-}, \mathrm{N}_{3}^{-}, \mathrm{NO}_{2}^{-}, \mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}, \mathrm{OCN}^{-}, \mathrm{I}^{-}$$

We need to analyze each of the ligands for possible isomeric linkages. Let's go through each ligand: 1. \(\mathrm{SCN}^{-}\): This ligand has a sulfur atom and a nitrogen atom that could bind to the metal center. 2. \(\mathrm{N}_{3}^{-}\): All three nitrogen atoms in this ligand are connected linearly, and only one end of the azide ion can bind to the metal center. 3. \(\mathrm{NO}_{2}^{-}\): This ligand has a nitrogen and an oxygen atom that could bind to the metal center. 4. \(\mathrm{NH}_{2}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{NH}_{2}\): There are only two nitrogen donor atoms in this ethylenediamine ligand, and, as they are located at either end of the ligand, they cannot provide alternative binding sites. 5. \(\mathrm{OCN}^{-}\): This ligand has an oxygen and a nitrogen atom that could bind to the metal center. 6. \(\mathrm{I}^{-}\): Iodide has only one iodine donor atom; there are no alternative binding sites.

Based on our analysis, the ligands capable of linkage isomerism are: 1. \(\mathrm{SCN}^{-}\): The metal center can bind to either sulfur or nitrogen. 2. \(\mathrm{NO}_{2}^{-}\): The metal center can bind to either nitrogen or oxygen. 3. \(\mathrm{OCN}^{-}\): The metal center can bind to either oxygen or nitrogen. Thus, the ligands \(\mathrm{SCN}^{-}\), \(\mathrm{NO}_{2}^{-}\), and \(\mathrm{OCN}^{-}\) are capable of linkage isomerism.