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Chapter 21: Problem 39

Give formulas for the following. a. potassium tetrachlorocobaltate(II) b. aquatricarbonylplatinum(II) bromide c. sodium dicyanobis(oxalato)ferrate(III) d. triamminechloroethylenediaminechromium(III) iodide

Short Answer

Expert verified
The short answer for the formulas of the coordination compounds is: a. Potassium tetrachlorocobaltate(II): \(K2[CoCl4]\) b. Aquatricarbonylplatinum(II) bromide: \([Pt(H2O)(CO)3]Br2\) c. Sodium dicyanobis(oxalato)ferrate(III): \(Na3[Fe(CN)2(C2O4)2]\) d. Triamminechloroethylenediaminechromium(III) iodide: \([Cr(NH3)3Cl(en)]I3\)

Step by step solution

01

a. Potassium tetrachlorocobaltate(II)

In this coordination compound, the central metal atom is cobalt (Co) with an oxidation state of +2 (indicated by II in the name). The ligands are four chloride ions (Cl-), and the counterion is potassium (K+). So the formula for potassium tetrachlorocobaltate(II) is: K2[CoCl4]
02

b. Aquatricarbonylplatinum(II) bromide

In this compound, the central metal atom is platinum (Pt) with an oxidation state of +2 (indicated by II in the name). The ligands are one water molecule (H2O) and three carbonyl ligands (CO). The counterion is bromide (Br-). So the formula for aquatricarbonylplatinum(II) bromide is: [Pt(H2O)(CO)3]Br2
03

c. Sodium dicyanobis(oxalato)ferrate(III)

In this compound, the central metal atom is iron (Fe) with an oxidation state of +3 (indicated by III in the name). The ligands are two cyanide ions (CN-) and two oxalato ligands (C2O4²-). The counterion is sodium (Na+). So the formula for sodium dicyanobis(oxalato)ferrate(III) is: Na3[Fe(CN)2(C2O4)2]
04

d. Triamminechloroethylenediaminechromium(III) iodide

In this compound, the central metal atom is chromium (Cr) with an oxidation state of +3 (indicated by III in the name). The ligands are three ammonia molecules (NH3), one chloride ion (Cl-), and one ethylenediamine ligand (en, C2H4(NH2)2). The counterion is iodide (I-). So the formula for triamminechloroethylenediaminechromium(III) iodide is: [Cr(NH3)3Cl(en)]I3

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Most popular questions from this chapter

Four different octahedral chromium coordination compounds exist that all have the same oxidation state for chromium and have \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{Cl}^{-}\) as the ligands and counterions. When 1 mole of each of the four compounds is dissolved in water, how many moles of silver chloride will precipitate upon addition of excess \(\mathrm{AgNO}_{3} ?\)

Consider aqueous solutions of the following coordination compounds: $\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{I}_{3}, \operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{4}, \mathrm{Na}_{2} \mathrm{Pt}_{6},$ and \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{3}\) . If aqueous AgNO \(_{3}\) is added to separate beakers containing solutions of each coordination compound, how many moles of AgI will precipitate per mole of transition metal present? Assume that each transition metal ion forms an octahedral complex.

Give formulas for the following. a. hexakis(pyridine)cobalt(III) chloride b. pentaammineiodochromium(III) iodide c. tris(ethylenediamine)nickel(II) bromide d. potassium tetracyanonickelate(II) e. tetraamminedichloroplatinum(IV) tetrachloroplatinate(II)

What is the lanthanide contraction? How does the lanthanide contraction affect the properties of the 4\(d\) and 5\(d\) transition metals?

The compound $\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6} \mathrm{Cl}_{2}$ is green, whereas \(\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{2}\) is violet. Predict the predominant color of light absorbed by each compound. Which compound absorbs light with the shorter wavelength? Predict in which compound \(\Delta\) is greater and whether \(\mathrm{H}_{2} \mathrm{O}\) or \(\mathrm{NH}_{3}\) is the stronger field ligand. Do your conclusions agree with the spectrochemical series?
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