Amino acids can act as ligands toward transition metal ions. The simplest amino acid is glycine $\left(\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2} \mathrm{H}\right) .$ Draw a structure of the glycinate anion \(\left(\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2}^{-}\right)\) acting as a bidentate ligand. Draw the structural isomers of the square planar complex \(\mathrm{Cu}\left(\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2}\right)_{2}\)

Short Answer

Expert verified
The glycinate anion structure is formed by deprotonating the carboxyl group in glycine, resulting in NH2CH2CO2-. As a bidentate ligand, glycinate forms two coordination bonds with metal ions; one through the amine nitrogen (N) and the other through the carboxylate oxygen (O). There are two structural isomers of the square planar complex Cu(NH2CH2CO2)2: 1. Cis configuration: The two amine nitrogen (N) atoms are adjacent in the complex, with the carboxylate oxygen (O) atoms also adjacent, occupying the other two corners of the square. 2. Trans configuration: The two amine nitrogen (N) atoms are opposite each other in the complex, with the carboxylate oxygen (O) atoms also opposite, occupying the other two corners of the square.

Step by step solution

01

Draw the structure of the glycinate anion

We will first draw the structure of the glycinate anion, which is NH2CH2CO2-. To do this, remove the H from the carboxyl group in glycine, NH2CH2CO2H, to form the deprotonated form, NH2CH2CO2-.
02

Show the glycinate anion acting as a bidentate ligand

As a bidentate ligand, the glycinate anion can form two coordination bonds with the metal ion, one through the amine nitrogen (N) and the other through the carboxylate oxygen (O). The structure of the bidentate glycinate anion should show these two points of coordination.
03

Draw the square planar complex Cu(NH2CH2CO2)2

Now we will draw the structural isomers of the square planar complex Cu(NH2CH2CO2)2. In a square planar complex, the central metal ion (Cu) is surrounded by the four coordination sites (two N and two O atoms from the two glycinate anions) at the corners of a square.
04

Isomer 1: Cis configuration

The first structural isomer has a cis configuration, in which the two amine nitrogen (N) atoms are adjacent to each other in the complex. The carboxylate oxygen (O) atoms are also adjacent, occupying the other two corners of the square.
05

Isomer 2: Trans configuration

The second structural isomer has a trans configuration, in which the two amine nitrogen (N) atoms are opposite each other in the complex. The carboxylate oxygen (O) atoms are also opposite, occupying the other two corners of the square.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What causes high-altitude sickness, and what is high-altitude acclimatization?

The compound $\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6} \mathrm{Cl}_{2}$ is green, whereas \(\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{Cl}_{2}\) is violet. Predict the predominant color of light absorbed by each compound. Which compound absorbs light with the shorter wavelength? Predict in which compound \(\Delta\) is greater and whether \(\mathrm{H}_{2} \mathrm{O}\) or \(\mathrm{NH}_{3}\) is the stronger field ligand. Do your conclusions agree with the spectrochemical series?

Almost all metals in nature are found as ionic compounds in ores instead of being in the pure state. Why? What must be done to a sample of ore to obtain a metal substance that has desirable properties?

The complex ion \(\operatorname{Ru}(\text { phen })_{3}^{2+}\) has been used as a probe for the structure of DNA. (Phen is a bidentate ligand.) a. What type of isomerism is found in $\operatorname{Ru}(\text { phen })_{3}^{2+} ?$ b. \(\operatorname{Ru}(\text { phen })_{3}^{2+}\) is diamagnetic (as are all complex ions of \(\mathrm{Ru}^{2+} \)). Draw the crystal field diagram for the \(d\) orbitals in this complex ion.

Draw geometrical isomers of each of the following complex ions. a. $\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}-$ b. \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{2}^{2+}\) c. \(\operatorname{Ir}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\) d. $\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{2} \mathrm{I}_{2}^{+}$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free