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Chapter 21: Problem 82

Name the following coordination compounds. a. $\operatorname{Na_t}_{4}\left[\operatorname{Ni}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]$ b. \(\mathrm{K}_{2}\left[\mathrm{CoCl}_{4}\right]\) c. \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) d. $\left[\mathrm{Co}(\mathrm{en})_{2}(\mathrm{SCN}) \mathrm{Cl}\right] \mathrm{Cl}$

Short Answer

Expert verified
The short answer for the given coordination compounds is as follows: a. Tetrasodium bis(oxalato)trinickel(II) b. Dipotassium tetra(chlorido)cobalt(II) c. Tetra(ammine)copper(II) sulfate d. Chlorido-di(ethylenediammine)-thiocyanato-cobalt(III) chloride

Step by step solution

01

1. Compound a: Identify the components

In compound a, the central atom is \(\operatorname{Ni}\) (nickel), and the ligands are \(\mathrm{C}_{2}\mathrm{O}_{4}\) (oxalate). There are four sodium ions \(\operatorname{Na_t}\) as counter ions.
02

2. Compound a: Name the compound

The ligands take the prefix "bis" since there are three oxalate ligands. Therefore, combining all these elements, compound a can be named as tetrasodium bis(oxalato)trinickel(II). The metal needs to have the oxidation state in roman numerals, which is (II) for nickel in this case.
03

3. Compound b: Identify the components

For compound b, the metal ion is \(\mathrm{Co}\) (cobalt), and the ligands are four \(\mathrm{Cl}\) (chloride) ions. Additionally, there are two potassium ions \(\mathrm{K}\) as counter ions.
04

4. Compound b: Name the compound

The ligand should be named as tetra(chlorido), and the oxidation state of cobalt is (II). Hence, compound b can be named as dipotassium tetra(chlorido)cobalt(II).
05

5. Compound c: Identify the components

In compound c, the central atom is \(\mathrm{Cu}\) (copper) with four \(\mathrm{NH}_{3}\) (ammine) ligands, and the counter ion is sulfate \(\mathrm{SO}_{4}\).
06

6. Compound c: Name the compound

The ligands are tetra(ammine). The oxidation state of copper is (II). Hence, compound c can be named as tetra(ammine)copper(II) sulfate.
07

7. Compound d: Identify the components

For compound d, the metal ion is \(\mathrm{Co}\) (cobalt), and the ligands are two \(\mathrm{en}\) (ethylenediamine), one \(\mathrm{SCN}\) (thiocyanato), and one \(\mathrm{Cl}\) (chlorido). There is an additional \(\mathrm{Cl}\) counter ion outside the coordination sphere.
08

8. Compound d: Name the compound

The ligands should be named as di(ethylenediammine), chlorido, and thiocyanato. As cobalt is the central atom, we should name the ligands in alphabetical order: chlorido first, followed by di(ethylenediammine) and then thiocyanato. The oxidation state of cobalt is (III). Hence, compound d can be named as chlorido-di(ethylenediammine)-thiocyanato-cobalt(III) chloride.

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Most popular questions from this chapter

A certain first-row transition metal ion forms many different colored solutions. When four coordination compounds of this metal, each having the same coordination number, are dissolved in water, the colors of the solutions are red, yellow, green, and blue. Further experiments reveal that two of the complex ions are paramagnetic with four unpaired electrons and the other two are diamagnetic. What can be deduced from this information about the four coordination compounds?

a. In the absorption spectrum of the complex ion \(\mathrm{Cr}(\mathrm{NCS})_{6}^{3-}\) there is a band corresponding to the absorption of a photon of light with an energy of $1.75 \times 10^{4} \mathrm{cm}^{-1} .\( Given \)1 \mathrm{cm}^{-1}=1.986 \times 10^{-23} \mathrm{J},$ what is the wavelength of this photon? b. The \(\mathrm{Cr}-\mathrm{N}-\mathrm{C}\) bond angle in \(\mathrm{Cr}(\mathrm{NCS})_{6}^{3-}\) is predicted to be \(180^{\circ} .\) What is the hybridization of the N atom in the \(\mathrm{NCS}^{-}\) ligand when a Lewis acid-base reaction occurs between \(\mathrm{Cr}^{3+}\) and \(\mathrm{NCS}^{-}\) that would give a $180^{\circ} \mathrm{Cr}-\mathrm{N}-\mathrm{C}$ bond angle? \(\mathrm{Cr}(\mathrm{NCS})_{6}^{3-}\) undergoes substitution by ethylenediamine (en) according to the equation $$\mathrm{Cr}(\mathrm{NCS})_{6}^{3-}+2 \mathrm{en} \longrightarrow \mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}^{+}+4 \mathrm{NCS}^{-}$$ Does \(\mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}^{+}\) exhibit geometric isomerism? Does \(\mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}^{+}\) exhibit optical isomerism?

The compound cisplatin, Pt \(\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2},\) has been studied extensively as an antitumor agent. The reaction for the synthesis of cisplatin is: $\mathrm{K}_{2} \mathrm{PtCl}_{4}(a q)+2 \mathrm{NH}_{3}(a q) \longrightarrow \mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}(s)+2 \mathrm{KCl}(a q)$ Write the electron configuration for platinum ion in cisplatin. Most \(d^{8}\) transition metal ions exhibit square planar geometry. With this and the name in mind, draw the structure of cisplatin.

Ethylenediaminetetraacetate (EDTA \(^{4-} )\) is used as a complexing agent in chemical analysis with the structure shown in Fig. \(21.7 .\) Solutions of EDTA \(^{4-}\) are used to treat heavy metal poisoning by removing the heavy metal in the form of a soluble complex ion. The complex ion virtually prevents the heavy metal ions from reacting with biochemical systems. The reaction of EDTA \(^{4-}\) with \(\mathrm{Pb}^{2+}\) is $$\mathrm{Pb}^{2+}(a q)+\mathrm{EDTA}^{4-(a q)} \rightleftharpoons \mathrm{PbEDTA}^{2-}(a q) \\\ \quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad K=1.1 \times 10^{18}$$ Consider a solution with 0.010 mol of \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) added to 1.0 \(\mathrm{L}\) of an aqueous solution buffered at \(\mathrm{pH}=13.00\) and containing 0.050$M \mathrm{Na}_{4} \mathrm{EDTA} .\( Does \)\mathrm{Pb}(\mathrm{OH})_{2}$ precipitate from this solution? $\left[K_{\mathrm{sp}} \text { for } \mathrm{Pb}(\mathrm{OH})_{2}=1.2 \times 10^{-15}\right]$

Oxalic acid is often used to remove rust stains. What properties of oxalic acid allow it to do this?
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