Chapter 22: Problem 35
There is only one compound that is named \(1,2-\) dichloroethane, but there are two distinct compounds that can be named \(1,2\) -dichloroethene. Why?
Chapter 22: Problem 35
There is only one compound that is named \(1,2-\) dichloroethane, but there are two distinct compounds that can be named \(1,2\) -dichloroethene. Why?
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Get started for freePolyesters containing double bonds are often crosslinked by reacting the polymer with styrene. a. Draw the structure of the copolymer of $\mathrm{HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{OH} \quad\( and \)\quad \mathrm{HO}_{2} \mathrm{C}-\mathrm{CH}=\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H}$ b. Draw the structure of the crosslinked polymer (after the polyester has been reacted with styrene).
A confused student was doing an isomer problem and listed the following six names as different structural isomers of \(\mathrm{C}_{7} \mathrm{H}_{16}\) a. 1 -sec-butylpropane b. 4 -methylhexane c. 2 -ethylpentane d. 1 -ethyl-1-methylbutane e. 3 -methylhexane f. 4 -ethylpentane How many different structural isomers are actually present in these six names?
If one hydrogen in a hydrocarbon is replaced by a halogen atom, the number of isomers that exist for the substituted compound depends on the number of types of hydrogen in the original hydrocarbon. Thus there is only one form of chloroethane (all hydrogens in ethane are equivalent), but there are two isomers of propane that arise from the substitution of a methyl hydrogen or a methylene hydrogen. How many isomers can be obtained when one hydrogen in each of the compounds named below is replaced by a chlorine atom? $$ \begin{array}{ll}{\text { a. } n \text { -pentane }} & {\text { c. } 2,4 \text { -dimethylpentane }} \\ {\text { b. } 2 \text { -methylbutane }} & {\text { d. methylcyclobutane }}\end{array} $$
Structural and optical isomers can be drawn having the formula $\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{F}$ . Give examples to illustrate these types of isomerism for \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{F}\) . Why can't \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{F}\) exhibit geometrical isomerism?
Give the structure of each of the following aromatic hydrocarbons. $$ \begin{array}{ll}{\text { a. } o \text { -ethyltoluene }} & {\text { c. } m \text { -diethylbenzene }} \\ {\text { b. } p \text { -di-tert-butylbenzene }} & {\text { d. } 1 \text { -phenyl-2-butene }}\end{array} $$
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