Name all the alcohols that have the formula $\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}$ . How many ethers have the formula \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O} ?\)

For alcohols, the general formula is \(\mathrm{R} - \mathrm{OH}\), where R can be any alkyl group. In this case, we have five carbon atoms. We can place the -OH group on different carbon atoms to form structural isomers. Here are the possible isomers: 1. Pentanol: \(CH_3-CH_2-CH_2-CH_2-CH_2-OH\) 2. 2-Methylbutanol: \(CH_3-CH_2-CH(CH_3)-CH_2-OH\) 3. 2,2-Dimethylpropanol: \(CH_3-C(CH_3)_2-CH_2-OH\) There are a total of three isomers for alcohols with the formula \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\).

For ethers, the general formula is \(\mathrm{R} - \mathrm{O} - \mathrm{R'}\), where R and R' can be the same or different alkyl groups. In this case, we have five carbon atoms to distribute among the two alkyl groups. We have the following possibilities to achieve a molecular formula of \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\): 1. Ethoxypropane: \(CH_3-CH_2-O-CH_2-CH_2-CH_3\) 2. Methoxybutane: \(CH_3-O-CH_2-CH_2-CH_2-CH_3\) 3. 1-Methoxy-2-methylpropane: \(CH_3-O-CH(CH_3)-CH_2-CH_3\) There are a total of three isomers for ethers with the formula \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\). So, there are three alcohols and three ethers that have the formula \(\mathrm{C}_{5} \mathrm{H}_{12} \mathrm{O}\).