How would you synthesize each of the following? a. 1,2-dibromopropane from propene b. acetone (2-propanone) from an alcohol c. tert-butyl alcohol (2-methyl-2-propanol) from an alkene (See Exercise 68.) d. propanoic acid from an alcohol

Short Answer

Expert verified
a. To synthesize 1,2-dibromopropane from propene, perform a halogenation reaction with an excess of Br2 under UV light. b. To synthesize acetone from an alcohol, oxidize 2-propanol using an oxidizing agent such as \(KMnO_4\) or \(H_2CrO_4\). c. (See Exercise 68.) d. To synthesize propanoic acid from an alcohol, oxidize 1-propanol using an oxidizing agent such as \(KMnO_4\) or \(H_2CrO_4\).

Step by step solution

01

Analyzing the reactants and the product

Propene is an alkene with the formula C3H6. The target molecule is 1,2-dibromopropane, a molecule with two bromine atoms attached to adjacent carbon atoms. The required reaction for this transformation is the addition of two bromine atoms to the double bond.
02

Performing the reaction

In order to synthesize 1,2-dibromopropane from propene, we need to perform a halogenation reaction with bromine (Br2). To do this, add an excess of Br2 to propene under UV light. The bromine molecules will be added across the double bond, resulting in 1,2-dibromopropane. b. acetone (2-propanone) from an alcohol
03

Analyzing the reactants and the product

The target molecule is acetone, a ketone with the formula \(C_3H_6O\). The starting material is an alcohol. The required reaction for this transformation is the oxidation of the secondary alcohol to a ketone.
04

Performing the reaction

To synthesize acetone from an alcohol, start with 2-propanol, a secondary alcohol, as the reactant. Oxidize 2-propanol using an oxidizing agent such as potassium permanganate (\(KMnO_4\)) or chromic acid (\(H_2CrO_4\)). This will convert the secondary alcohol to a ketone, forming acetone (2-propanone). c. tert-butyl alcohol (2-methyl-2-propanol) from an alkene (See Exercise 68.) d. propanoic acid from an alcohol
05

Analyzing the reactants and the product

The target molecule is propanoic acid, a carboxylic acid with the formula \(C_2H_5COOH\). The starting material is an alcohol. The required reaction for this transformation is the oxidation of a primary alcohol to a carboxylic acid.
06

Performing the reaction

To synthesize propanoic acid from an alcohol, start with 1-propanol, a primary alcohol, as the reactant. Oxidize 1-propanol using an oxidizing agent such as potassium permanganate (\(KMnO_4\)) or chromic acid (\(H_2CrO_4\)). This will convert the primary alcohol to a carboxylic acid, forming propanoic acid.

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