Complete the following reactions. $$ \begin{array}{l}{\text { a. } \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}+\mathrm{CH}_{3} \mathrm{OH} \rightarrow} \\ {\text { b. } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}+\mathrm{HCOOH} \rightarrow}\end{array} $$

Short Answer

Expert verified
The short answer to the given reactions is: a. CH3CO2H + CH3OH → CH3CO2CH3 + H2O b. CH3CH2CH2OH + HCOOH → HCOO(CH2)3CH3 + H2O

Step by step solution

01

Identify the esterification process in reaction a.

In an esterification reaction, the carboxylic acid (CH3CO2H) reacts with an alcohol (CH3OH) to form an ester and water as a by-product. The hydroxyl group (-OH) from the acid and hydrogen (H) from the alcohol combine to form water (H2O), while the remaining parts combine to form the ester.
02

Complete reaction a.

Considering the esterification process described in Step 1, we have: CH3CO2H + CH3OH → CH3CO2CH3 + H2O The ester formed in this reaction is called methyl acetate (CH3CO2CH3).
03

Identify the esterification process in reaction b.

Similar to reaction a, we have a carboxylic acid (HCOOH) reacting with an alcohol (CH3CH2CH2OH). The esterification process involves the formation of water and an ester.
04

Complete reaction b.

Following the esterification process, the completed reaction is: CH3CH2CH2OH + HCOOH → HCOO(CH2)3CH3 + H2O The ester formed in this reaction is called propyl formate (HCOO(CH2)3CH3). The completed reactions are: a. CH3CO2H + CH3OH → CH3CO2CH3 + H2O b. CH3CH2CH2OH + HCOOH → HCOO(CH2)3CH3 + H2O

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Most popular questions from this chapter

Polyesters containing double bonds are often crosslinked by reacting the polymer with styrene. a. Draw the structure of the copolymer of $\mathrm{HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{OH} \quad\( and \)\quad \mathrm{HO}_{2} \mathrm{C}-\mathrm{CH}=\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H}$ b. Draw the structure of the crosslinked polymer (after the polyester has been reacted with styrene).

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