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Chapter 3: Problem 113

The compound cisplatin, $\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2},$ has been studied as an antitumor agent. Cisplatin is synthesized as follows: $$ \mathrm{K}_{2} \mathrm{PtCl}_{4}(a q)+2 \mathrm{NH}_{3}(a q) \rightarrow \operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}(s)+2 \mathrm{KCl}(a q) $$ What mass of cisplatin can be produced from \(100 .\) g of $\mathrm{K}_{2} \mathrm{PtCl}_{4}\( and sufficient \)\mathrm{NH}_{3} ?$

Short Answer

Expert verified
The mass of cisplatin that can be produced from 100 grams of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\) and sufficient \(\mathrm{NH}_{3}\) is approximately 79.49 grams.

Step by step solution

01

Calculate the molar mass of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\)

First, we need to find the number of moles in 100g of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\). To do this, we have to find the molar mass of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\). Using periodic table, we can find the atomic mass of each element: Molar mass of K = 39.10 g/mol, Molar mass of Pt = 195.08 g/mol, Molar mass of Cl = 35.45 g/mol. So, the molar mass of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\) is: Molar Mass = (2 × 39.10) + (1 × 195.08) + (4 × 35.45) g/mol = 78.20 + 195.08 + 141.80 g/mol = 415.08 g/mol.
02

Find the moles of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\)

To find the moles of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\), we can use the formula: Moles = Mass (g) / Molar Mass (g/mol) Moles of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\) = 100g / 415.08 g/mol = 0.2409 mol. Note that the stoichiometry of the given equation implies that one mole of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\) reacts to form one mole of cisplatin, as we can see: \(\mathrm{K}_{2}\mathrm{PtCl}_{4}(a q)+2\mathrm{NH}_{3}(a q)\rightarrow \mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\mathrm{Cl}_{2}(s)+2\mathrm{KCl}(a q)\).
03

Calculate the molar mass of cisplatin

To find the mass of cisplatin produced, we first need to calculate the molar mass of \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\). Using periodic table, we can find the atomic mass of Pt, N, and H: Molar mass of Pt = 195.08 g/mol, Molar mass of N = 14.01 g/mol, Molar mass of H = 1.008 g/mol, Molar mass of Cl = 35.45 g/mol. So, the molar mass of \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\) is: Molar Mass = (1 × 195.08) + (4 × 14.01) + (8 × 1.008) + (2 × 35.45) g/mol= 195.08 + 56.04 + 8.084 + 70.90 g/mol = 330.104 g/mol.
04

Calculate the mass of cisplatin produced

Now, we can calculate the mass of cisplatin produced by using the moles of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\) and the mole-to-mole relation between it and cisplatin: Moles of cisplatin = 0.2409 mol Now, we can convert the moles of cisplatin to mass: Mass of cisplatin = Moles × Molar Mass = 0.2409 mol × 330.104 g/mol = 79.49 grams. So, the mass of cisplatin that can be produced from 100 grams of \(\mathrm{K}_{2}\mathrm{PtCl}_{4}\) and sufficient \(\mathrm{NH}_{3}\) is approximately 79.49 grams.

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Most popular questions from this chapter

Para-cresol, a substance used as a disinfectant and in the manufacture of several herbicides, is a molecule that contains the elements carbon, hydrogen, and oxygen. Complete combustion of a \(0.345-\mathrm{g}\) sample of \(p\) -cresol produced 0.983 g carbon dioxide and 0.230 \(\mathrm{g}\) water. Determine the empirical formula for \(p\) -cresol.

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