Boron consists of two isotopes, 10 \(\mathrm{B}\) and 11 \(\mathrm{B}\) . Chlorine also has two isotopes, 35 \(\mathrm{Cl}\) and 37 \(\mathrm{Cl}\) . Consider the mass spectrum of \(\mathrm{BCl}_{3}\) . How many peaks would be present, and what approximate mass would each peak correspond to in the BCl_ mass spectrum?

Short Answer

Expert verified
There would be 8 peaks in the mass spectrum of BCl₃, with corresponding approximate masses of 115, 116, 117, 118, 119, 120, 121, and 122.

Step by step solution

01

List all possible combinations of boron and chlorine isotopes in BCl₃

For each boron isotope, there are three possible chlorine isotopes. So, for both boron isotopes, we have: - B⁽¹⁰⁾Cl₃ - B⁽¹¹⁾Cl₃ For each BCl₃, there are 3 chlorine atoms with two possible isotopes each (35Cl and 37Cl), resulting in 2³ = 8 combinations. Therefore, we have: - B⁽¹⁰⁾Cl₃: 8 combinations - B⁽¹¹⁾Cl₃: 8 combinations Total possible combinations: 8 + 8 = 16
02

Find the number of unique approximate masses

Now, we'll look for unique masses by considering the mass of each combination. The approximate mass of BCl₃ is the sum of the mass of the boron isotope and the three chlorine isotopes. For B⁽¹⁰⁾Cl₃: 1. 10 + 3(35) = 115 2. 10 + 2(35) + 37 = 117 3. 10 + 35 + 2(37) = 119 4. 10 + 3(37) = 121 For B⁽¹¹⁾Cl₃: 1. 11 + 3(35) = 116 2. 11 + 2(35) + 37 = 118 3. 11 + 35 + 2(37) = 120 4. 11 + 3(37) = 122 The unique approximate masses are 115, 116, 117, 118, 119, 120, 121, and 122.
03

Determine the number of peaks and their corresponding approximate masses

We have 8 unique approximate masses, which means there will be 8 peaks in the mass spectrum of BCl₃. The approximate masses corresponding to these peaks are: - 115 - 116 - 117 - 118 - 119 - 120 - 121 - 122 So, there would be 8 peaks in the mass spectrum of BCl₃, with approximate masses of 115, 116, 117, 118, 119, 120, 121, and 122.

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