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Chapter 3: Problem 146

Some bismuth tablets, a medication used to treat upset stomachs, contain 262 \(\mathrm{mg}\) of bismuth subsalicylate, $\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{BiO}_{4},$ per tablet. Assuming two tablets are digested, calculate the mass of bismuth consumed.

Short Answer

Expert verified
The mass of bismuth consumed when two bismuth tablets are digested is approximately 302.412 mg.

Step by step solution

01

Find the molar mass of bismuth subsalicylate (C₇H₅BiO₄)

To find the molar mass of bismuth subsalicylate (C₇H₅BiO₄), we must find the sum of the molar masses of its constituent elements. The molar mass of carbon (C): 12.01 g/mol The molar mass of hydrogen (H): 1.01 g/mol The molar mass of bismuth (Bi): 208.98 g/mol The molar mass of oxygen (O): 16.00 g/mol Now, we calculate the molar mass of C₇H₅BiO₄: Molar mass = 7(12.01) + 5(1.01) + 208.98 + 4(16.00) = 84.07 + 5.05 + 208.98 + 64.00 = 362.10 g/mol
02

Calculate the mass of bismuth in one tablet

First, let's find the mass fraction of bismuth in bismuth subsalicylate: Mass fraction of bismuth = (mass of Bi in the compound) / (molar mass of C₇H₅BiO₄) = (208.98 g/mol) / (362.10 g/mol) The mass fraction of bismuth is approximately 0.577. Now, we can find the mass of bismuth in one tablet by multiplying the mass of bismuth subsalicylate in one tablet by the mass fraction of bismuth: Mass of bismuth in one tablet = 262 mg × 0.577 = 151.206 mg (approximately)
03

Calculate the mass of bismuth in two tablets

Now, we can simply multiply the mass of bismuth in one tablet by the number of tablets (2) to find the total mass of bismuth consumed: Mass of bismuth in two tablets = 2 × 151.206 mg = 302.412 mg (approximately) The mass of bismuth consumed when two bismuth tablets are digested is approximately 302.412 mg.

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