According to the law of conservation of mass, mass cannot be gained or destroyed in a chemical reaction. Why can’t you simply add the masses of two reactants to determine the total mass of product?

Short Answer

Expert verified
Simply adding the masses of the reactants to determine the total mass of the product is insufficient because it ignores the rearrangement of atoms and their respective bonding patterns in a chemical reaction. Instead, we need to balance the chemical equation and apply the law of conservation of mass to accurately determine the mass of the products. This ensures that the total number of atoms for each element on the reactant side is equal to the corresponding number of atoms on the product side, thus conserving mass.

Step by step solution

01

Understand the Law of Conservation of Mass

The law of conservation of mass states that the total mass of reactants in a closed system remains constant throughout a chemical reaction and is equal to the total mass of the products. This means that mass is conserved and not created or destroyed during a chemical reaction.
02

Consider the Nature of Chemical Reactions

In a chemical reaction, atoms of the reactants are rearranged to form products. While the total number of atoms remains the same, the way they are combined differs between the reactants and the products. A chemical reaction is a process in which bonds between atoms are broken and new ones are formed to create a new substance.
03

Realize that Adding Masses of Reactants is not the Same as Counting Atoms

Since a chemical reaction involves the rearrangement of atoms, simply adding the masses of the reactants does not take into account how these atoms are combined in the products. In fact, it is crucial to balance the chemical equation to ensure the conservation of mass. In a balanced chemical equation, the number of atoms for each element on the reactant side must be equal to the corresponding number of atoms on the product side.
04

Balancing Chemical Equations

To determine the mass of the product, one must first balance the chemical equation and then apply the law of conservation of mass. This means that the total mass of the reactants must be equal to the total mass of the products, and the coefficients in the balanced equation can be used to calculate the mass by multiplying them by their respective molar masses. To sum up, simply adding the masses of the reactants is not sufficient to determine the mass of the products because it ignores the rearrangement of atoms and their respective bonding patterns in a chemical reaction. Instead, we need to balance the chemical equation and apply the law of conservation of mass to accurately determine the mass of the products.

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Most popular questions from this chapter

Hexamethylenediamine $\left(\mathrm{C}_{6} \mathrm{H}_{6} \mathrm{N}_{2}\right)$ is one of the starting materials for the production of nylon. It can be prepared from adipic acid $\left(\mathrm{C}_{6} \mathrm{H}_{10} \mathrm{O}_{4}\right)$ by the following overall equation: $$ \mathrm{C}_{6} \mathrm{H}_{10} \mathrm{O}_{4}(l)+2 \mathrm{NH}_{3}(g)+4 \mathrm{H}_{2}(g) \rightarrow \mathrm{C}_{6} \mathrm{H}_{16} \mathrm{N}_{2}(l)+4 \mathrm{H}_{2} \mathrm{O}(l) $$ What is the percent yield for the reaction if 765 g of hexamethylenediamine is made from \(1.00 \times 10^{3} \mathrm{g}\) of adipic acid?

Maleic acid is an organic compound composed of \(41.39 \% \mathrm{C},\) 3.47$\% \mathrm{H}$ , and the rest oxygen. If 0.129 mole of maleic acid has a mass of 15.0 \(\mathrm{g}\) , what are the empirical and molecular formulas of maleic acid?

Fungal laccase, a blue protein found in wood-rotting fungi, is 0.390$\% \mathrm{Cu}$ by mass. If a fungal laccase molecule contains four copper atoms, what is the molar mass of fungal laccase?

In the production of printed circuit boards for the electronics industry, a 0.60 -mm layer of copper is laminated onto an insulating plastic board. Next, a circuit pattern made of a chemically resistant polymer is printed on the board. The unwanted copper is removed by chemical etching, and the protective polymer is finally removed by solvents. One etching reaction is $$ \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q)+\mathrm{Cu}(s) \longrightarrow $$ $$ 2 \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}(a q) $$ A plant needs to manufacture \(10,000\) printed circuit boards, each $8.0 \times 16.0 \mathrm{cm}\( in area. An average of \)80 . \%$ of the copper is removed from each board (density of copper \(=8.96 \mathrm{g} / \mathrm{cm}^{3}\) . What masses of \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) are needed to do this? Assume 100\(\%\) yield.

Determine the molecular formulas to which the following empirical formulas and molar masses pertain. a. \(\operatorname{SNH}(188.35 \mathrm{g} / \mathrm{mol})\) b. \(\mathrm{NPCl}_{2}(347.64 \mathrm{g} / \mathrm{mol})\) c. \(\operatorname{CoC}_{4} \mathrm{O}_{4}(341.94 \mathrm{g} / \mathrm{mol})\) d. \(\mathrm{SN}(184.32 \mathrm{g} / \mathrm{mol})\)

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