Avogadro’s number, molar mass, and the chemical formula of a compound are three useful conversion factors. What unit conversions can be accomplished using these conversion factors?

Short Answer

Expert verified
Using Avogadro's number, we can convert between moles and particles. With molar mass, we can convert between moles and mass in grams. Lastly, the chemical formula allows us to convert between masses or moles of different elements in a compound and determine the mass percent of an element in that compound.

Step by step solution

01

1. Avogadro's Number

Avogadro's number (\(6.022 \times 10^{23}\)) is a fundamental constant that relates the number of particles (atoms, molecules, ions, etc.) in one mole of a substance. It can be used for the following unit conversions: 1. Moles to particles: To convert from moles to particles (atoms, molecules, ions, etc.), multiply the number of moles by Avogadro's number. 2. Particles to moles: To convert from particles to moles, divide the number of particles by Avogadro's number.
02

2. Molar Mass

Molar mass is the mass (in grams) of one mole of a substance. It is determined by summing the atomic masses of the elements in a compound, with each atomic mass weighted by the number of times the element appears in the compound. Molar mass can be used for the following unit conversions: 1. Moles to mass (grams): To convert from moles to grams, multiply the number of moles by the molar mass of the substance. 2. Mass (grams) to moles: To convert from grams to moles, divide the mass of the substance by its molar mass.
03

3. Chemical Formula

The chemical formula of a compound indicates the proportion of each element in the compound, providing information about the composition of the compound. It can be used for the following unit conversions: 1. Mass of one element to mass of another element in a compound: To convert the mass of one element in a compound to the mass of another element in the same compound, use the mole ratio from the chemical formula and the molar mass of each element. 2. Moles of one element to moles of another element in a compound: To convert the moles of one element in a compound to the moles of another element in the same compound, use the mole ratio from the chemical formula. 3. Mass percent of an element in a compound: To find the mass percent of an element in a compound, divide the mass contribution of that element (atomic mass multiplied by the number of atoms of that element in the compound) by the molar mass of the compound, and multiply the result by 100. In summary, Avogadro's number, molar mass, and the chemical formula of a compound can be used to accomplish various unit conversions related to moles, particles, mass, and composition.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the spring of \(1984,\) concern arose over the presence of ethylene dibromide, or EDB, in grains and cereals. EDB has the molecular formula \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{Br}_{2}\) and until 1984 was commonly used as a plant fumigant. The federal limit for \(\mathrm{EDB}\) in finished cereal products is 30.0 parts per billion (ppb), where \(1.0 \mathrm{ppb}=\) \(1.0 \times 10^{-9} \mathrm{g}\) of \(\mathrm{EDB}\) for every 1.0 \(\mathrm{g}\) of sample. How many molecules of EDB are in 1.0 lb of flour if 30.0 ppb of EDB is present?

Balance the following equations representing combustion reactions: c. $C_{12} \mathrm{H}_{22} \mathrm{O}_{11}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)$ d. Fe \((s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}(s)\) e. $\mathrm{FeO}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}(s)$

You take 1.00 g of an aspirin tablet (a compound consisting solely of carbon, hydrogen, and oxygen), burn it in air, and collect 2.20 $\mathrm{g} \mathrm{CO}_{2}\( and 0.400 \)\mathrm{g} \mathrm{H}_{2} \mathrm{O} .$ You know that the molar mass of aspirin is between 170 and 190 $\mathrm{g} / \mathrm{mol}\( . Reacting 1 \)\mathrm{mole}$ of salicylic acid with 1 mole of acetic anhydride \(\left(\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{3}\right)\) gives you 1 mole of aspirin and 1 mole of acetic acid $\left(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{2}\right)$ Use this information to determine the molecular formula of salicylic acid.

Balance the following equations: a. $\mathrm{Ca}(\mathrm{OH})_{2}(a q)+\mathrm{H}_{3} \mathrm{PO}_{4}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)$ b. $\mathrm{Al}(\mathrm{OH})_{3}(s)+\mathrm{HCl}(a q) \rightarrow \mathrm{AlCl}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$ c. $\mathrm{AgNO}_{3}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{Ag}_{2} \mathrm{SO}_{4}(s)+\mathrm{HNO}_{3}(a q)$

A sample of urea contains $1.121 \mathrm{g} \mathrm{N}, 0.161 \mathrm{g} \mathrm{H}, 0.480 \mathrm{g} \mathrm{C}\( and 0.640 \)\mathrm{g}$ O. What is the empirical formula of urea?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free