Many oxidation–reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each reaction, identify the substance reduced and the substance oxidized. a. $\mathrm{Al}(s)+\mathrm{HCl}(a q) \rightarrow \mathrm{AlCl}_{3}(a q)+\mathrm{H}_{2}(g)$ b. $\mathrm{CH}_{4}(g)+\mathrm{S}(s) \rightarrow \mathrm{CS}_{2}(l)+\mathrm{H}_{2} \mathrm{S}(g)$ c. $\mathrm{C}_{3} \mathrm{H}_{8}(g)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(i)$ d. $\mathrm{Cu}(s)+\mathrm{Ag}^{+}(a q) \rightarrow \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q)$

Short Answer

Expert verified
a. Balanced equation: \(2\mathrm{Al}(s)+6\mathrm{HCl}(a q) \rightarrow 2\mathrm{AlCl}_{3}(a q)+3\mathrm{H}_{2}(g)\). Oxidized: \(\mathrm{Al}\), Reduced: \(\mathrm{H}\) from \(\mathrm{HCl}\) b. Balanced equation: \(\mathrm{CH}_{4}(g)+2\mathrm{S}(s) \rightarrow \mathrm{CS}_{2}(l)+2\mathrm{H}_{2}\mathrm{S}(g)\). Oxidized: \(\mathrm{C}\) from \(\mathrm{CH}_{4}\), Reduced: \(\mathrm{S}\) c. Balanced equation: \(\mathrm{C}_{3} \mathrm{H}_{8}(g)+5\mathrm{O}_{2}(g) \rightarrow 3\mathrm{CO}_{2}(g)+4\mathrm{H}_{2} \mathrm{O}(l)\). Oxidized: \(\mathrm{C}\) and \(\mathrm{H}\) from \(\mathrm{C}_{3}\mathrm{H}_{8}\), Reduced: \(\mathrm{O}_{2}\) d. Balanced equation: \(\mathrm{Cu}(s)+\mathrm{Ag}^{+}(a q) \rightarrow \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q)\). Oxidized: \(\mathrm{Cu}\), Reduced: \(\mathrm{Ag}^{+}\)

Step by step solution

01

Recognize the Redox Reaction

In this reaction, Aluminum (\(\mathrm{Al}\)) reacts with Hydrochloric acid (\(\mathrm{HCl}\)) to produce Aluminum chloride (\(\mathrm{AlCl}_{3}\)) and Hydrogen gas (\(\mathrm{H}_{2}\)). Aluminum loses electrons in the process, while Hydrogen gains electrons. Thus, this is a redox reaction.
02

Balance the Equation

To balance the equation, we need to ensure that the number of atoms for each element is equal on both sides of the equation: \(\underline{2}\mathrm{Al}(s)+\underline{6}\mathrm{HCl}(a q) \rightarrow \underline{2}\mathrm{AlCl}_{3}(a q)+\underline{3}\mathrm{H}_{2}(g)\) Now, the equation is balanced.
03

Identify the Oxidized and Reduced Species

In this reaction, Aluminum (\(\mathrm{Al}\)) is oxidized as it loses electrons, and Hydrogen, from Hydrochloric acid (\(\mathrm{HCl}\)), is reduced as it gains electrons. b. \(\mathrm{CH}_{4}(g)+\mathrm{S}(s) \rightarrow \mathrm{CS}_{2}(l)+\mathrm{H}_{2}\mathrm{S}(g)\)
04

Recognize the Redox Reaction

In this reaction, Methane (\(\mathrm{CH}_{4}\)) reacts with Sulfur (\(\mathrm{S}\)) to produce Carbon disulfide (\(\mathrm{CS}_{2}\)) and Hydrogen sulfide (\(\mathrm{H}_{2}\mathrm{S}\)). Carbon loses electrons, while Sulfur gains electrons. Thus, this is a redox reaction.
05

Balance the Equation

To balance the equation, we need to ensure that the number of atoms for each element is equal on both sides of the equation: \(\mathrm{CH}_{4}(g)+\underline{2}\mathrm{S}(s) \rightarrow \mathrm{CS}_{2}(l)+\underline{2}\mathrm{H}_{2}\mathrm{S}(g)\) Now, the equation is balanced.
06

Identify the Oxidized and Reduced Species

In this reaction, Carbon, from Methane (\(\mathrm{CH}_{4}\)), is oxidized as it loses electrons, and Sulfur (\(\mathrm{S}\)) is reduced as it gains electrons. c. \(\mathrm{C}_{3}\mathrm{H}_{8}(g)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2}\mathrm{O}(l)\)
07

Recognize the Redox Reaction

In this reaction, Propane (\(\mathrm{C}_{3}\mathrm{H}_{8}\)) reacts with Oxygen (\(\mathrm{O}_{2}\)) to produce Carbon dioxide (\(\mathrm{CO}_{2}\)) and Water (\(\mathrm{H}_{2}\mathrm{O}\)). Carbon and Hydrogen lose electrons, while Oxygen gains electrons. Thus, this is a redox reaction.
08

Balance the Equation

To balance the equation, we need to ensure that the number of atoms for each element is equal on both sides of the equation: \(\mathrm{C}_{3} \mathrm{H}_{8}(g)+\underline{5}\mathrm{O}_{2}(g) \rightarrow \underline{3}\mathrm{CO}_{2}(g)+\underline{4}\mathrm{H}_{2} \mathrm{O}(l)\) Now, the equation is balanced.
09

Identify the Oxidized and Reduced Species

In this reaction, Carbon and Hydrogen, from Propane (\(\mathrm{C}_{3}\mathrm{H}_{8}\)), are oxidized as they lose electrons, and Oxygen (\(\mathrm{O}_{2}\)) is reduced as it gains electrons. d. \(\mathrm{Cu}(s)+\mathrm{Ag}^{+}(a q) \rightarrow \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q)\)
10

Recognize the Redox Reaction

In this reaction, Copper (\(\mathrm{Cu}\)) reacts with Silver ion (\(\mathrm{Ag}^{+}\)) to produce Silver (\(\mathrm{Ag}\)) and Copper ion (\(\mathrm{Cu}^{2+}\)). Copper loses electrons, while Silver gains electrons. Thus, this is a redox reaction.
11

Balance the Equation

To balance the equation, we need to ensure that the number of atoms for each element is equal on both sides of the equation: The equation is already balanced: \(\mathrm{Cu}(s)+\mathrm{Ag}^{+}(a q) \rightarrow \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q)\)
12

Identify the Oxidized and Reduced Species

In this reaction, Copper (\(\mathrm{Cu}\)) is oxidized as it loses electrons, and Silver ion (\(\mathrm{Ag}^{+}\)) is reduced as it gains electrons.

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Most popular questions from this chapter

Consider a 1.50-g mixture of magnesium nitrate and magnesium chloride. After dissolving this mixture in water, 0.500 M silver nitrate is added dropwise until precipitate formation is complete. The mass of the white precipitate formed is 0.641 g. a. Calculate the mass percent of magnesium chloride in the mixture. b. Determine the minimum volume of silver nitrate that must have been added to ensure complete formation of the precipitate.

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