For the following chemical reactions, determine the precipitate produced when the two reactants listed below are mixed together. Indicate “none” if no precipitate will form $\mathrm{Sr}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{K}_{3} \mathrm{PO}_{4}(a q) \longrightarrow$__________________(s) $\mathrm{K}_{2} \mathrm{CO}_{3}(a q)+\mathrm{AgNO}_{3}(a q) \longrightarrow$__________________(s) $\mathrm{NaCl}(a q)+\mathrm{KNO}_{3}(a q) \longrightarrow$__________________(s) $\mathrm{KCl}(a q)+\mathrm{AgNO}_{3}(a q) \longrightarrow$__________________(s) $\mathrm{FeCl}_{3}(a q)+\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q) \longrightarrow$__________________(s)

Short Answer

Expert verified
The precipitates formed in the given chemical reactions are as follows: 1. \(Sr_3(PO_4)_2 (s)\) 2. \(Ag_2CO_3 (s)\) 3. None 4. \(AgCl (s)\) 5. \(PbCl_2 (s)\)

Step by step solution

01

Familiarize yourself with solubility rules

To predict precipitation, we need to know the solubility rules. Some general solubility rules are: - Most nitrate (\(NO_3^-\)), acetate (\(CH_3COO^-\)), and perchlorate (\(ClO_4^-\)) salts are soluble. - Most alkali metal (group 1A) salts and ammonium \((NH_4^+)\) salts are soluble. - Most chloride, bromide, and iodide salts are soluble, except for those with silver (\(Ag^+\)), lead (\(Pb^{2+}\)), and mercury (\(Hg_2^{2+}\)) cations. - Most sulfate (\(SO_4^{2-}\)) salts are soluble, except for those with calcium (\(Ca^{2+}\)), strontium (\(Sr^{2+}\)), barium (\(Ba^{2+}\)), mercury (\(Hg_{2}^{2+}\)), and lead (\(Pb^{2+}\)) cations. - Most hydroxide salts are slightly soluble or insoluble, except those with alkali metals and calcium, which are soluble. - Most sulfide, carbonate (\(CO_3^{2-}\)), chromate (\(CrO_4^{2-}\)), and phosphate (\(PO_4^{3-}\)) salts are insoluble, except for those with alkali metals and ammonium.
02

Determine the possible products

Based on the reactants, determine the possible products by exchanging ions between various reactants. 1. \(Sr(NO_3)_2 (aq) + K_3PO_4 (aq) \longrightarrow Sr_3(PO_4)_2 (s) + 6KNO_3 (aq)\) 2. \(K_2CO_3 (aq) + AgNO_3 (aq) \longrightarrow 2Ag_2CO_3 (s) + 2KNO_3 (aq)\) 3. \(NaCl (aq) + KNO_3 (aq) \longrightarrow NaNO_3 (aq) + KCl (aq)\) 4. \(KCl (aq) + AgNO_3 (aq) \longrightarrow AgCl (s) + KNO_3 (aq)\) 5. \(FeCl_3 (aq) + Pb(NO_3)_2 (aq) \longrightarrow 3PbCl_2 (s) + 2Fe(NO_3)_3 (aq)\)
03

Predict the precipitates using solubility rules

Use solubility rules to determine which of the possible products will form a precipitate. 1. \(Sr(NO_3)_2 (aq) + K_3PO_4 (aq) \longrightarrow Sr_3(PO_4)_2 (s) + 6KNO_3 (aq)\) - Soluble: \(KNO_3\) - Insoluble: \(Sr_3(PO_4)_2\) - Precipitate: \(Sr_3(PO_4)_2\) 2. \(K_2CO_3 (aq) + AgNO_3 (aq) \longrightarrow 2Ag_2CO_3 (s) + 2KNO_3 (aq)\) - Soluble: \(KNO_3\) - Insoluble: \(Ag_2CO_3\) - Precipitate: \(Ag_2CO_3\) 3. \(NaCl (aq) + KNO_3 (aq) \longrightarrow NaNO_3 (aq) + KCl (aq)\) - Soluble: \(NaNO_3, KCl\) - No precipitate. 4. \(KCl (aq) + AgNO_3 (aq) \longrightarrow AgCl (s) + KNO_3 (aq)\) - Soluble: \(KNO_3\) - Insoluble: \(AgCl\) - Precipitate: \(AgCl\) 5. \(FeCl_3 (aq) + Pb(NO_3)_2 (aq) \longrightarrow 3PbCl_2 (s) + 2Fe(NO_3)_3 (aq)\) - Soluble: \(Fe(NO_3)_3\) - Insoluble: \(PbCl_2\) - Precipitate: \(PbCl_2\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider reacting copper(II) sulfate with iron. Two possible reactions can occur, as represented by the following equations. $$\operatorname{copper}(\mathrm{II}) \text { sulfate }(a q)+\mathrm{iron}(s) \longrightarrow (s)+\operatorname{iron}(\mathrm{II}) \text { sulfate }(a q)$$ $$\operatorname{copper}(\mathrm{II}) \text { sulfate }(a q)+\mathrm{iron}(s) \longrightarrow (s)+\text { iron (III) sulfate }(a q) $$ You place 87.7 mL of a 0.500-M solution of copper(II) sulfate in a beaker. You then add 2.00 g of iron filings to the copper(II) sulfate solution. After one of the above reactions occurs, you isolate 2.27 g of copper. Which equation above describes the reaction that occurred? Support your answer

What mass of solid AgBr is produced when 100.0 \(\mathrm{mL}\) of 0.150 \(\mathrm{MAgNO}_{3}\) is added to 20.0 \(\mathrm{mL}\) of 1.00 $\mathrm{M} \mathrm{NaBr} ?$

What volume of 0.0200 M calcium hydroxide is required to neutralize 35.00 mL of 0.0500 M nitric acid?

You wish to prepare 1 L of a 0.02-M potassium iodate solution. You require that the final concentration be within 1% of 0.02 M and that the concentration must be known accurately to the fourth decimal place. How would you prepare this solution? Specify the glassware you would use, the accuracy needed for the balance, and the ranges of acceptable masses of \(\mathrm{KIO}_{3}\) that can be used

Polychlorinated biphenyls (PCBs) have been used extensively as dielectric materials in electrical transformers. Because PCBs have been shown to be potentially harmful, analysis for their presence in the environment has become very important. PCBs are manufactured according to the following generic reaction: $$\mathrm{C}_{12} \mathrm{H}_{10}+n \mathrm{Cl}_{2} \rightarrow \mathrm{C}_{12} \mathrm{H}_{10-n} \mathrm{Cl}_{n}+n \mathrm{HCl} $$ This reaction results in a mixture of \(\mathrm{PCB}\) products. The mixture is analyzed by decomposing the PCBs and then precipitating the resulting \(\mathrm{Cl}^{-}\) as AgCl. a. Develop a general equation that relates the average value of n to the mass of a given mixture of PCBs and the mass of AgCl produced. b. A 0.1947-g sample of a commercial PCB yielded 0.4791 g of AgCl. What is the average value of n for this sample?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free