A mixture contains only sodium chloride and potassium chloride. A 0.1586-g sample of the mixture was dissolved in water. It took 22.90 mL of 0.1000 M AgNO3 to completely precipitate all the chloride present. What is the composition (by mass percent) of the mixture?

Short Answer

Expert verified
The mass percent of NaCl and KCl together in the mixture is 51.14%. However, we cannot determine the mass percentage for each compound individually due to the lack of information on the ratio between NaCl and KCl in the mixture.

Step by step solution

01

Write the chemical reactions involved

First, we need to write the chemical reactions between sodium chloride, potassium chloride, and silver nitrate. The reactions are: NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq) KCl(aq) + AgNO3(aq) → AgCl(s) + KNO3(aq) Both reactions have a 1:1 mole ratio between the chloride salts (both sodium and potassium) and the silver nitrate.
02

Calculate moles of chloride ions using the volume and molarity of AgNO3

We are given that it takes 22.90 mL of 0.1000 M AgNO3 solution to react with all the chloride ions present in the sample. First, convert the volume of AgNO3 to liters: 22.90 mL × (1 L / 1000 mL) = 0.0229 L Next, calculate the moles of chloride ions that reacted with AgNO3 using its molarity: moles of Cl- ions = molarity of AgNO3 × volume of AgNO3 in L moles of Cl- ions = 0.1000 mol/L × 0.0229 L moles of Cl- ions = 0.00229 mol
03

Calculate mass of total chloride ions in the sample

We have the moles of chloride ions. Now we need to find their mass. Mass of Cl- ions = moles of Cl- ions × molar mass of Cl Mass of Cl- ions = 0.00229 mol × 35.45 g/mol Mass of Cl- ions = 0.0811 g
04

Calculate mass percent of NaCl and KCl in the mixture

The mass of the total chloride ions contains the sum of the mass of chloride ions from both NaCl and KCl. We have the mass of total chloride ions (0.0811 g) and the mass of the sample (0.1586 g). We can calculate the mass percent of NaCl and KCl in the mixture using the mass of chloride ions. Mass percent of NaCl + KCl = (Mass of Cl- ions / Mass of the sample) × 100% Mass percent of NaCl + KCl = (0.0811 g / 0.1586 g) × 100% Mass percent of NaCl + KCl = 51.14% Since the mixture only has NaCl and KCl, the mass percent of NaCl and KCl together in the mixture is 51.14%. Due to the lack of information about the ratio between NaCl and KCl in the mixture, and since the chloride ions were the only factor considered in the reaction to determine the percentages, we can't determine the mass percentage for each compound individually (NaCl and KCl).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Polychlorinated biphenyls (PCBs) have been used extensively as dielectric materials in electrical transformers. Because PCBs have been shown to be potentially harmful, analysis for their presence in the environment has become very important. PCBs are manufactured according to the following generic reaction: $$\mathrm{C}_{12} \mathrm{H}_{10}+n \mathrm{Cl}_{2} \rightarrow \mathrm{C}_{12} \mathrm{H}_{10-n} \mathrm{Cl}_{n}+n \mathrm{HCl} $$ This reaction results in a mixture of \(\mathrm{PCB}\) products. The mixture is analyzed by decomposing the PCBs and then precipitating the resulting \(\mathrm{Cl}^{-}\) as AgCl. a. Develop a general equation that relates the average value of n to the mass of a given mixture of PCBs and the mass of AgCl produced. b. A 0.1947-g sample of a commercial PCB yielded 0.4791 g of AgCl. What is the average value of n for this sample?

Consider a 1.50-g mixture of magnesium nitrate and magnesium chloride. After dissolving this mixture in water, 0.500 M silver nitrate is added dropwise until precipitate formation is complete. The mass of the white precipitate formed is 0.641 g. a. Calculate the mass percent of magnesium chloride in the mixture. b. Determine the minimum volume of silver nitrate that must have been added to ensure complete formation of the precipitate.

Balance the following oxidation–reduction reactions that occur in basic solution. a. $\mathrm{Al}(s)+\mathrm{MnO}_{4}^{-}(a q) \rightarrow \mathrm{MnO}_{2}(s)+\mathrm{Al}(\mathrm{OH})_{4}-(a q)$ b. \(\mathrm{Cl}_{2}(g) \rightarrow \mathrm{Cl}^{-}(a q)+\mathrm{OCl}^{-}(a q)\) c. $\mathrm{NO}_{2}^{-}(a q)+\mathrm{Al}(s) \rightarrow \mathrm{NH}_{3}(g)+\mathrm{AlO}_{2}^{-}(a q)$

Write the balanced formula, complete ionic, and net ionic equations for each of the following acid–base reactions. a. \(\mathrm{HClO}_{4}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(s) \rightarrow\) b. \(\mathrm{HCN}(a q)+\mathrm{NaOH}(a q) \rightarrow\) c. \(\mathrm{HCl}(a q)+\mathrm{NaOH}(a q) \rightarrow\)

Zinc and magnesium metal each react with hydrochloric acid according to the following equations: $$\mathrm{Zn}(s)+2 \mathrm{HCl}(a q) \longrightarrow \mathrm{ZnCl}_{2}(a q)+\mathrm{H}_{2}(g)$$ $$\mathrm{Mg}(s)+2 \mathrm{HCl}(a q) \longrightarrow \mathrm{MgCl}_{2}(a q)+\mathrm{H}_{2}(g)$$ A 10.00-g mixture of zinc and magnesium is reacted with the stoichiometric amount of hydrochloric acid. The reaction mixture is then reacted with 156 mL of 3.00 M silver nitrate to produce the maximum possible amount of silver chloride. a. Determine the percent magnesium by mass in the original mixture. b. If 78.0 mL of HCl was added, what was the concentration of the HCl?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free