Consider an experiment in which two burets, Y and Z, are simultaneously draining into a beaker that initially contained 275.0 mL of 0.300 M HCl. Buret Y contains 0.150 M NaOH and buret Z contains 0.250 M KOH. The stoichiometric point in the titration is reached 60.65 minutes after Y and Z were started simultaneously. The total volume in the beaker at the stoichiometric point is 655 mL. Calculate the flow rates of burets Y and Z. Assume the flow rates remain constant during the experiment.

The flow rates for burets Y and Z can be calculated by first finding the moles of HCl, NaOH, and KOH at the stoichiometric point. We find that initially, there are 82.5 mmol of HCl. At the stoichiometric point, we can write 82.5 mmol = Moles of NaOH + Moles of KOH. The total volume of NaOH and KOH at the stoichiometric point is 380 mL. By setting up and solving a system of two linear equations, we determine the volumes of NaOH (V_NaOH) and KOH (V_KOH). Finally, we calculate the flow rates of burets Y and Z by dividing the volumes of NaOH and KOH by the time (60.65 minutes). The flow rates are given as follows: Flow rate of buret Y \(= \frac{V_{NaOH}}{60.65}\) minutes Flow rate of buret Z \(= \frac{V_{KOH}}{60.65}\) minutes