What mass of NaOH is contained in 250.0 mL of a 0.400 M sodium hydroxide solution?

Short Answer

Expert verified
The mass of NaOH in a 250.0 mL of a 0.400 M sodium hydroxide solution is 4.00 grams.

Step by step solution

01

Find the number of moles of NaOH contained in the solution

To calculate the number of moles of NaOH in the solution, we can use the formula: number of moles = molarity × volume Since we know the molarity (0.400 M) and volume (250.0 mL), we can plug these values into the formula: number of moles = 0.400 mol/L × 0.250 L Note that we need to convert the volume from milliliters to liters by dividing by 1000 (1 L = 1000 mL).
02

Calculate the number of moles of NaOH

Now we can multiply the molarity and volume to find the number of moles of NaOH: number of moles = 0.400 mol/L × 0.250 L = 0.100 mol
03

Calculate the molar mass of NaOH

To convert the number of moles of NaOH to mass, we need to know the molar mass of NaOH. The molar mass can be found by adding the molar masses of each element in the compound: Molar mass of NaOH = molar mass of Na + molar mass of O + molar mass of H Using the periodic table, we can find the molar masses of each element: - Molar mass of Na = 22.99 g/mol - Molar mass of O = 16.00 g/mol - Molar mass of H = 1.01 g/mol So, the molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol
04

Calculate the mass of NaOH in the solution

Now that we have the molar mass of NaOH and the number of moles present in the solution, we can calculate the mass of NaOH using the formula: mass = number of moles × molar mass mass of NaOH = 0.100 mol × 40.00 g/mol = 4.00 g So, there are 4.00 grams of NaOH contained in 250.0 mL of a 0.400 M sodium hydroxide solution.

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