Specify which of the following equations represent oxidation– reduction reactions, and indicate the oxidizing agent, the reducing agent, the species being oxidized, and the species being reduced a. $\mathrm{CH}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(g) \rightarrow \mathrm{CO}(g)+3 \mathrm{H}_{2}(g)$ b. $2 \mathrm{AgNO}_{3}(a q)+\mathrm{Cu}(s) \rightarrow \mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}(a q)+2 \mathrm{Ag}(s)$ c. $\mathrm{Zn}(s)+2 \mathrm{HCl}(a q) \rightarrow \mathrm{ZnCl}_{2}(a q)+\mathrm{H}_{2}(g)$ d. $2 \mathrm{H}^{+}(a q)+2 \mathrm{CrO}_{4}^{2-}(a q) \rightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$

Short Answer

Expert verified
The redox reactions are a, b, and c. The oxidizing and reducing agents are: a. Oxidizing agent: Water; Reducing agent: Methane b. Oxidizing agent: Silver nitrate; Reducing agent: Copper c. Oxidizing agent: Hydrochloric acid; Reducing agent: Zinc

Step by step solution

01

Identify oxidation-reduction (redox) reactions

For each equation, assign oxidation numbers to the elements. If the oxidation numbers change from reactants to products, the equation is a redox reaction. a. \(CH_4(g)+H_2O(g) \rightarrow CO(g)+3H_2(g)\) - Assign oxidation numbers: C: -4 to +2, H: +1 to 0, O: -2 - Oxidation numbers change, so this is a redox reaction. b. \(2AgNO_3(aq)+Cu(s) \rightarrow Cu(NO_3)_2(aq)+2Ag(s)\) - Assign oxidation numbers: Ag: +1 to 0, N: +5, O: -2, Cu: 0 to +2 - Oxidation numbers change, so this is a redox reaction. c. \(Zn(s)+2HCl(aq) \rightarrow ZnCl_2(aq)+H_2(g)\) - Assign oxidation numbers: Zn: 0 to +2, H: +1 to 0, Cl: -1 - Oxidation numbers change, so this is a redox reaction. d. \(2H^+(aq)+2CrO_4^{2-}(aq) \rightarrow Cr_2O_7^{2-}(aq)+H_2O(l)\) - Assign oxidation numbers: H: +1, Cr: +6 to +6, O: -2 - Oxidation numbers do not change, so this is not a redox reaction.
02

Determine oxidizing and reducing agents

For each redox reaction, identify the species that cause the oxidation and reduction by determining which species gained or lost electrons. a. \(CH_4(g)+H_2O(g) \rightarrow CO(g)+3H_2(g)\) - Oxidation: C is oxidized from -4 to +2 (loses electrons) - Reduction: H is reduced from +1 to 0 (gains electrons) - Oxidizing agent: Water - Reducing agent: Methane b. \(2AgNO_3(aq)+Cu(s) \rightarrow Cu(NO_3)_2(aq)+2Ag(s)\) - Oxidation: Cu is oxidized from 0 to +2 (loses electrons) - Reduction: Ag is reduced from +1 to 0 (gains electrons) - Oxidizing agent: Silver nitrate - Reducing agent: Copper c. \(Zn(s)+2HCl(aq) \rightarrow ZnCl_2(aq)+H_2(g)\) - Oxidation: Zn is oxidized from 0 to +2 (loses electrons) - Reduction: H is reduced from +1 to 0 (gains electrons) - Oxidizing agent: Hydrochloric acid - Reducing agent: Zinc
03

Summary

The redox reactions are a, b, and c. The oxidation and reduction species, along with their corresponding agents, are as follows: a. Oxidizing agent: Water; Reducing agent: Methane b. Oxidizing agent: Silver nitrate; Reducing agent: Copper c. Oxidizing agent: Hydrochloric acid; Reducing agent: Zinc

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A stream flows at a rate of \(5.00 \times 10^{4}\) liters per second (L/s) upstream of a manufacturing plant. The plant discharges $3.50 \times 10^{3} \mathrm{L} / \mathrm{s}\( of water that contains 65.0 \)\mathrm{ppm} \mathrm{HCl}$ into the stream. (See Exercise 135 for definitions.) a. Calculate the stream's total flow rate downstream from this plant. b. Calculate the concentration of \(\mathrm{HCl}\) in ppm downstream from this plant. c. Further downstream, another manufacturing plant diverts $1.80 \times 10^{4} \mathrm{L} / \mathrm{s}$ of water from the stream for its own use. This plant must first neutralize the acid and does so by adding lime: $$\mathrm{CaO}(s)+2 \mathrm{H}^{+}(a q) \longrightarrow \mathrm{Ca}^{2+}(a q)+\mathrm{H}_{2} \mathrm{O}(i) $$ What mass of CaO is consumed in an 8.00-h work day by this plant? d. The original stream water contained 10.2 \(\mathrm{ppm} \mathrm{Ca}^{2+}\) . Although no calcium was in the waste water from the first plant, the waste water of the second plant contains \(\mathrm{Ca}^{2+}\) from the neutralization process. If 90.0% of the water used by the second plant is returned to the stream, calculate the concentration of \(\mathrm{Ca}^{2+}\) in ppm downstream of the second plant.

What mass of iron(III) hydroxide precipitate can be produced by reacting 75.0 mL of 0.105 M iron(III) nitrate with 125 mL of 0.150 M sodium hydroxide?

A 25.00-mL sample of hydrochloric acid solution requires 24.16 mL of 0.106 M sodium hydroxide for complete neutralization. What is the concentration of the original hydrochloric acid solution?

Write net ionic equations for the reaction, if any, that occurs when aqueous solutions of the following are mixed. a. ammonium sulfate and barium nitrate b. lead(II) nitrate and sodium chloride c. sodium phosphate and potassium nitrate d. sodium bromide and rubidium chloride e. copper(II) chloride and sodium hydroxide

A 1.00-g sample of an alkaline earth metal chloride is treated with excess silver nitrate. All of the chloride is recovered as 1.38 g of silver chloride. Identify the metal.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free