Write an equation to show how sulfuric acids in acid rain reacts with marble and limestone. (Both marble and limestone are primarily calcium carbonate.)

Short Answer

Expert verified
\(H_2SO_4 + CaCO_3 \rightarrow CaSO_4 + H_2O + CO_2\)

Step by step solution

01

Write the unbalanced equation

First, let's write out the unbalanced chemical equation using the chemical formulas for the reactants and products: H2SO4 + CaCO3 → CaSO4 + H2O + CO2
02

Balance the equation

Now, we need to balance the equation by ensuring that there are equal numbers of each element on both sides of the equation. Let's examine the equation element by element: - H (Hydrogen): We have 2 hydrogen atoms in sulfuric acid (H2SO4), and 2 hydrogen atoms in water (H2O). - S (Sulfur): There is 1 sulfur atom in sulfuric acid (H2SO4), and 1 sulfur atom in calcium sulfate (CaSO4). - O (Oxygen): We have 4 oxygen atoms in sulfuric acid (H2SO4), 3 in calcium carbonate (CaCO3), 4 in calcium sulfate (CaSO4), 1 in water (H2O), and 2 in carbon dioxide (CO2). This totals to 7 oxygen atoms on the reactant side and 7 oxygen atoms on the product side. - Ca (Calcium): There is 1 calcium atom in calcium carbonate (CaCO3) and 1 calcium atom in calcium sulfate (CaSO4). - C (Carbon): We have 1 carbon atom in calcium carbonate (CaCO3) and 1 carbon atom in carbon dioxide (CO2). As it turns out, the original unbalanced equation is actually balanced: H2SO4 + CaCO3 → CaSO4 + H2O + CO2
03

Write the balanced equation

Now that we have balanced the equation, let's write it out in its final form: \(H_2SO_4 + CaCO_3 \rightarrow CaSO_4 + H_2O + CO_2\) This balanced equation represents the reaction between sulfuric acid in acid rain and calcium carbonate in marble and limestone, producing calcium sulfate, water, and carbon dioxide.

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Most popular questions from this chapter

Metallic molybdenum can be produced from the mineral molybdenite, \(\mathrm{MoS}_{2}\). The mineral is first oxidized in air to molybdenum trioxide and sulfur dioxide. Molybdenum trioxide is then reduced to metallic molybdenum using hydrogen gas. The balanced equations are $$\operatorname{MoS}_{2}(s)+\frac{7}{2} \mathrm{O}_{2}(g) \longrightarrow \operatorname{MoO}_{3}(s)+2 \mathrm{SO}_{2}(g)$$ $$\mathrm{MoO}_{3}(s)+3 \mathrm{H}_{2}(g) \longrightarrow \mathrm{Mo}(s)+3 \mathrm{H}_{2} \mathrm{O}(l)$$ Calculate the volumes of air and hydrogen gas at \(17^{\circ} \mathrm{C}\) and 1.00 atm that are necessary to produce \(1.00 \times 10^{3} \mathrm{kg}\) pure molybdenum from \(\mathrm{MoS}_{2}\) . Assume air contains 21\(\%\) oxygen by volume, and assume 100\(\%\) yield for each reaction.

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