A student adds 4.00 g of dry ice (solid \(\mathrm{CO}_{2} )\) to an empty balloon. What will be the volume of the balloon at STP after all the dry ice sublimes (converts to gaseous \(\mathrm{CO}_{2} ) ?\)

Short Answer

Expert verified
After the 4.00 g of dry ice sublimes, the volume of the balloon at STP (Standard Temperature and Pressure) will be approximately 2.04 L.

Step by step solution

01

Calculate the moles of CO2

First, we need to find the number of moles of CO2 using the given mass and molar mass of CO2. Molar mass of CO2: C = 12.01 g/mol O = 16.00 g/mol Molar mass of CO2 = 1 × C + 2 × O = 1 × 12.01 g/mol + 2 × 16.00 g/mol = 44.01 g/mol Given mass of CO2: 4.00 g Now, we can calculate the number of moles (n) of CO2: n = (given mass) / (molar mass) n = 4.00 g / 44.01 g/mol ≈ 0.0909 mol
02

Calculate the volume of the balloon using Ideal Gas Law

Now that we have the number of moles of CO2 and the conditions are at STP, we can use the Ideal Gas Law equation to find the volume of the balloon. At STP, Temperature (T) = 273.15 K Pressure (P) = 1 atm Ideal Gas Law equation: \(PV=nRT\) We want to find the volume (V). Rearrange the equation for solving 'V': V = (nRT) / P Put the values into the equation and solve for the volume (V): V = (0.0909 mol × 0.0821 L atm/mol K × 273.15 K) / (1 atm) V = 2.0434 L So, after all the dry ice sublimes, the volume of the balloon at STP would be approximately 2.04 L.

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Most popular questions from this chapter

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