What is the difference between \(\Delta H\) and \(\Delta E ?\)

Short Answer

Expert verified
The difference between \(\Delta H\) (change in enthalpy) and \(\Delta E\) (change in internal energy) depends on the change in the product of pressure and volume during a process or reaction. While \(\Delta H\) represents the total energy of a system, including both its internal energy and the energy related to its pressure and volume, \(\Delta E\) refers only to the total energy stored in a system. The relationship between \(\Delta H\) and \(\Delta E\) is given by: \(\Delta H = \Delta E + \Delta (PV)\). The difference between the two depends on the specific conditions of the process or reaction.

Step by step solution

01

Define Enthalpy (H) and Internal Energy (E)

Enthalpy (H) is a thermodynamic property that represents the total energy of a system, including both its internal energy (E) and the energy related to its pressure and volume. It is defined as: \(H = E + PV\) Where, \(H\) is enthalpy, \(E\) is internal energy, \(P\) is pressure, and \(V\) is volume. Internal Energy (E) is the total energy stored in a system, including kinetic energy, potential energy and other forms of energy (including molecular bonds, electron configuration, etc.).
02

Define the Changes in Enthalpy (\(\Delta H\)) and Internal Energy (\(\Delta E\))

The change in enthalpy (\(\Delta H\)) represents the difference in the enthalpy of a system before and after a process or reaction has taken place. Similarly, the change in internal energy (\(\Delta E\)) represents the difference in the internal energy of a system before and after a process or reaction has occurred. Mathematically, these changes are represented as: \(\Delta H = H_{final} - H_{initial}\) \(\Delta E = E_{final} - E_{initial}\)
03

Explain the Relationship between \(\Delta H\) and \(\Delta E\)

From the definition of enthalpy, we know that: \(H = E + PV\) Taking the change in enthalpy and change in internal energy, we can write: \(\Delta H = \Delta E + \Delta (PV)\) This equation shows that the difference between the changes in enthalpy (\(\Delta H\)) and internal energy (\(\Delta E\)) depends on the change in the product of pressure and volume during a process or reaction. In some cases, \(\Delta H\) and \(\Delta E\) may be equal or approximately equal, such as when the process or reaction occurs under constant volume or constant pressure conditions, and the system does not perform any work. In general, the difference between the two depends on the specific conditions of the process or reaction.

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Most popular questions from this chapter

A piston performs work of \(210 . \mathrm{L} \cdot\) atm on the surroundings, while the cylinder in which it is placed expands from \(10 . \mathrm{L}\) to 25 \(\mathrm{L}\) . At the same time, 45 \(\mathrm{J}\) of heat is transferred from the surroundings to the system. Against what pressure was the piston working?

It has been determined that the body can generate 5500 \(\mathrm{kJ}\) of energy during one hour of strenuous exercise. Perspiration is the body's mechanism for eliminating this heat. What mass of water would have to be evaporated through perspiration to rid the body of the heat generated during 2 hours of exercise? (The heat of vaporization of water is 40.6 \(\mathrm{kJ} / \mathrm{mol.} )\)

Consider 2.00 moles of an ideal gas that are taken from state \(A\) \(\left(P_{A}=2.00 \mathrm{atm}, V_{A}=10.0 \mathrm{L}\right)\) to state \(B\left(P_{B}=1.00 \mathrm{atm}, V_{B}=\right.\) 30.0 \(\mathrm{L}\) ) by two different pathways: These pathways are summarized on the following graph of \(P\) versus \(V :\) Calculate the work (in units of \(\mathrm{J} )\) associated with the two path- ways. Is work a state function? Explain.

Consider a balloon filled with helium at the following conditions. $$ \begin{array}{l}{313 \mathrm{g} \mathrm{He}} \\ {1.00 \mathrm{atm}} \\ {1910 . \mathrm{L}} \\ {\text { Molar Heat Capacity }=20.8 \mathrm{J} / \mathrm{C} \cdot \mathrm{mol}}\end{array} $$ The temperature of this balloon is decreased by \(41.6^{\circ} \mathrm{C}\) as the volume decreases to \(1643 \mathrm{L},\) with the pressure remaining constant. Determine \(q, w,\) and $\Delta E(\text { in } \mathrm{kJ} \text { ) for the compression of }$ the balloon.

Calculate \(\Delta E\) for each of the following. a. \(q=-47 \mathrm{kJ}, w=+88 \mathrm{kJ}\) b. \(q=+82 \mathrm{kJ}, w=-47 \mathrm{kJ}\) c. \(q=+47 \mathrm{kJ}, w=0\) d. In which of these cases do the surroundings do work on the system?

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