A system undergoes a process consisting of the following two steps: Step 1: The system absorbs 72 \(\mathrm{J}\) of heat while 35 \(\mathrm{J}\) of work is done on it. Step \(2 :\) The system absorbs 35 \(\mathrm{J}\) of heat while performing 72 \(\mathrm{J}\) of work. Calculate \(\Delta E\) for the overall process.

Short Answer

Expert verified
The overall change in internal energy for the process is \(\Delta E_\text{total} = 144 \mathrm{J}\).

Step by step solution

01

Calculate Change in Internal Energy for the First Step

In the first step, the system absorbs 72 J of heat (\(Q_1\)) and has 35 J of work done on it (\(W_1\)). Since work is done on the system, we must use a positive sign for \(W_1\). Thus, we can calculate the change in internal energy for the first step as: $$\Delta E_1 = Q_1 - W_1 = 72 - 35 = 37 \mathrm{J}$$
02

Calculate Change in Internal Energy for the Second Step

In the second step, the system absorbs 35 J of heat (\(Q_2\)) and performs 72 J of work (\(W_2\)). Since work is done by the system, we must use a negative sign for \(W_2\). Thus, we can calculate the change in internal energy for the second step as: $$\Delta E_2 = Q_2 - W_2 = 35 - (-72) = 35 + 72 = 107 \mathrm{J}$$
03

Calculate the Overall Change in Internal Energy

Now that we have both ΔE₁ and ΔE₂, we can calculate the overall change in internal energy by combining these values: $$\Delta E_\text{total} = \Delta E_1 + \Delta E_2 = 37 + 107 = 144 \mathrm{J}$$ So, the overall change in internal energy for the process is 144 J.

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