If the internal energy of a thermodynamic system is increased by $300 . \mathrm{J}\( while 75 \)\mathrm{J}$ of expansion work is done, how much heat was transferred and in which direction, to or from the system?

Short Answer

Expert verified
In this thermodynamic process, 375 J of heat was transferred to the system.

Step by step solution

01

Identify the known and unknown variables

We are given: 1. The increase in internal energy, ∆U = 300 J 2. Work done by the system, W = 75 J We need to find the heat transferred, Q, and its direction (to or from the system).
02

Write down the equation for the first law of thermodynamics

The first law of thermodynamics for a closed system can be stated as: ∆U = Q - W where ∆U is the change in internal energy, Q is the heat transferred, and W is the work done by the system.
03

Substitute the known values and find Q

Now we can substitute the given values into the equation: \(300 \text{ J} = Q - 75 \text{ J}\) To solve for Q, add 75 J to both sides of the equation: \(Q = 300 \text{ J} + 75 \text{ J}\)
04

Calculate the heat transferred and determine its direction

Do the arithmetic to find the value of Q: \(Q = 375 \text{ J}\) The sign of Q is positive, which indicates that heat was transferred to the system. If Q was negative, that would mean heat was transferred from the system.
05

Final Answer

In this thermodynamic process, 375 J of heat was transferred to the system.

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