The energy content of food is typically determined using a bomb calorimeter. Consider the combustion of a \(0.30-\mathrm{g}\) sample of butter in a bomb calorimeter having a heat capacity of 2.67 \(\mathrm{kJ}^{\prime} \mathrm{C}\) . If the temperature of the calorimeter increases from \(23.5^{\circ} \mathrm{C}\) to \(27.3^{\circ} \mathrm{C}\) , calculate the energy of combustion per gram of butter.

To calculate the energy of combustion per gram of butter, first find the change in temperature (ΔT) by subtracting the initial temperature from the final temperature: \(ΔT = 27.3°C - 23.5°C = 3.8°C\). Next, calculate the heat released (q) during combustion using the formula \(q = C × ΔT\), where C is the heat capacity of the calorimeter (2.67 kJ/°C): \(q = (2.67 kJ/°C) × (3.8°C) = 10.146 kJ\). Finally, find the energy of combustion per gram of butter by dividing the heat released (q) by the mass of the butter sample: \(Energy\; of\; combustion\; per\; gram\; of\; butter = (10.146 kJ) / (0.30 g) = 33.82 kJ/g\). Therefore, the energy of combustion per gram of butter is approximately 33.82 kJ/g.