Some automobiles and buses have been equipped to burn propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right) .\) Compare the amounts of energy that can be obtained per gram of \(\mathrm{C}_{3} \mathrm{H}_{8}(g)\) and per gram of gasoline, assuming that gasoline is pure octane, $\mathrm{C}_{8} \mathrm{H}_{18}(l) .\( See Example \)6.11 .$ ) Look up the boiling point of propane. What disadvantages are there to using propane instead of gasoline as a fuel?

Short Answer

Expert verified
In comparing propane (C3H8) and gasoline (assumed to be pure octane, C8H18), propane produces about \(2.46\, kJ/g\) more energy than octane per gram (\(-50.34\, kJ/g\) for propane and \(-47.88\, kJ/g\) for octane). However, propane has a low boiling point of \(-42^\circ C\) and must be stored in pressurized tanks, leading to increased weight and complex fuel systems. Additionally, propane has lower energy density than gasoline, resulting in larger fuel tanks and lower range before refueling. Infrastructures for propane fueling stations are not as widespread as gasoline, posing difficulties in finding refueling options. Furthermore, propane handling and maintenance require special training and may pose increased safety hazards.

Step by step solution

01

Write the balanced combustion reactions for propane and octane

For this step, we'll write the balanced combustion reactions for both propane and octane. Combustion reactions involve reacting with oxygen to produce carbon dioxide and water. For propane: C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(l) For octane: C8H18(l) + 12.5O2(g) -> 8CO2(g) + 9H2O(l)
02

Calculate the energy produced per gram for propane and octane

To compare the amounts of energy produced per gram of propane and octane, we'll need their enthalpy of combustion values. The enthalpy of combustion for propane is \(-\,2220.0\, kJ/mol\), and for octane, it is \(-\,5471.0\, kJ/mol\). The molar mass of propane is \(44.10\, g/mol\) and that for octane is \(114.22\, g/mol\). Now, we will calculate the amount of energy produced per gram by dividing the enthalpy of combustion by the molar mass. For propane: Energy per gram = \(\frac{-2220.0\, kJ/mol}{44.10\, g/mol} = -50.34\, kJ/g\) For octane: Energy per gram = \(\frac{-5471.0\, kJ/mol}{114.22\, g/mol} = -47.88\, kJ/g\)
03

Compare the energy produced per gram of propane and octane

From the calculations in step 2, we can compare the energy produced per gram of propane and octane: Propane: \(-50.34\, kJ/g\) Octane: \(-47.88\, kJ/g\) Propane produces around \(2.46\, kJ/g\) more energy than octane per gram.
04

Look up the boiling point of propane

The boiling point of propane is \(-42^\circ C\).
05

Identify disadvantages of using propane instead of gasoline as a fuel

Some disadvantages of using propane as a fuel instead of gasoline are: 1. Due to its lower boiling point, propane must be stored in pressurized tanks, which leads to increased weight and more complex fuel systems. 2. Propane has lower energy density than gasoline, which means that vehicles running on propane will need larger fuel tanks and have a lower range before refueling compared to vehicles running on gasoline. 3. The infrastructure for propane fueling stations is not as widespread as gasoline, making it difficult to find refueling options, especially in remote areas. 4. Propane handling and maintenance require special training, and potential safety hazards to the vehicle owner and the mechanic increase. In conclusion, while propane can produce more energy per gram compared to gasoline, the disadvantages of using propane as a fuel are the low boiling point, complex storage system, lower energy density, and less developed infrastructure.

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