Element 106 has been named seaborgium, Sg, in honor of Glenn Seaborg, discoverer of the first transuranium element. a. Write the expected electron configuration for element 106. b. What other element would be most like element 106 in its properties? c. Predict the formula for a possible oxide and a possible oxyanion of element 106.

Short Answer

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a. The electron configuration of Seaborgium (Sg) is [Rn] 5f¹⁴ 6d⁴ 7s². b. Seaborgium is most similar to Chromium (Cr), Molybdenum (Mo), and Tungsten (W). c. A possible oxide formula is SgO₃, and a possible oxyanion formula is (SgO₄)²⁻.

Step by step solution

01

Determine the electron configuration of Seaborgium (Sg)

Seaborgium, Sg, is element 106, which means it has 106 electrons in its neutral state. Using the periodic table, we can find the electron configuration for Seaborgium as follows: 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², 4f¹⁴, 5d¹⁰, 6p⁶, 7s², 5f¹⁴, 6d⁴ So, the electron configuration of Seaborgium is [Rn] 5f¹⁴ 6d⁴ 7s².
02

Identify the element most similar in properties to Seaborgium

Seaborgium belongs to Group 6 in the periodic table, along with Chromium, Molybdenum, and Tungsten. These elements share similar properties because they have the same number of valence electrons. Therefore, Seaborgium would be most similar to Chromium (Cr), Molybdenum (Mo), and Tungsten (W).
03

Predict the formula for a possible oxide of Seaborgium

The elements in Group 6 typically form oxides with a charge of +6, i.e., they lose six valence electrons when forming an oxide compound. The oxygen atom gains two electrons and has a charge of -2. Therefore, the formula for a possible oxide of Seaborgium would be SgO₃.
04

Predict the formula for a possible oxyanion of Seaborgium

A common oxyanion formed by Group 6 elements is the molybdate [(MoO₄)²⁻] and chromate [(CrO₄)²⁻] ions. Following this trend, we can predict that a possible oxyanion for Seaborgium would have the formula (SgO₄)²⁻.

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