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Chapter 7: Problem 142

Small daily doses of lithium carbonate taken orally are often given to treat manic-depressive psychoses. This dosage maintains the level of lithium ion in the blood at about \(1 \times 10^{-3} \mathrm{mol} / \mathrm{L}\) . a. What is the formula of lithium carbonate? b. What mass of lithium ion is present per liter of blood in these patients?

Short Answer

Expert verified
a. The formula of lithium carbonate is \(Li_2CO_3\). b. To find the mass of lithium ions per liter of blood, we have \(\displaystyle 1\times 10^{-3}\ \mathrm{mol\ L^{-1}}\times \frac{6.94\ \mathrm{g}}{1\ \mathrm{mol}} = 6.94\times 10^{-3}\ \mathrm{g\ L^{-1}}\). So, there is \(6.94 \times 10^{-3} \, \mathrm{g}\) of lithium ion present per liter of blood in these patients.

Step by step solution

01

a. Find the formula of lithium carbonate

Lithium (Li) is an alkali metal with a +1 charge, and carbonate (CO₃) is a polyatomic ion with a -2 charge. To determine the formula of lithium carbonate, we need to balance the charges. Lithium (Li) has a +1 charge and carbonate (CO₃) has a -2 charge. We need to have two Li atoms (+1 each) to balance the -2 charge of the carbonate ion. So, the formula for lithium carbonate is Li₂CO₃.

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